The amount of the extra snow would a child need to take a snowball will be 636.71 cubic cm.
<h3>What is the volume of the sphere?</h3>
Let d be the diameter of the sphere.
Then the volume of the sphere will be
V = 1/6 πd³ cubic units
Then the amount of the extra snow would a child need to take a snowball with a diameter of 8 cm and increase its size to a snowball with a diameter of 12 cm will be
Amount of snow = 1/6 π x 12³ - 1/6 π x 8³
Amount of snow = 288 π - 85.33π
Amount of snow = 636.71 cubic cm
More about the volume of the sphere link is given below.
brainly.com/question/9994313
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Answer:
(-9/7,-26/7)
[more detailed at the bottom of the explanation]
Step-by-step explanation:
I am assuming that this is a system of equations...
So, knowing that y is equal to x + 5, you would plug that in the second equation and find x. Then you would plug x and find y.
—————
Step 1)
Equation 1:
y = (x + 5)
Equation 2:
5x + 2y = 1
Equation 2 can also be written as:
5x + 2(x+5) = 1
I wrote x+5 instead of y because the first equation tells us that y is equal to x + 5.
—————
Step 2)
Solve for x .
5x + 2(x+5) = 1
5x + 2x + 10 = 1
7x + 10 = 1
7x = 1 - 10
7x = -9
x = -9/7
—————
Step 3)
Plug the x value back in the first equation.
y = -9/7 + 5
y = -26/7
—————
Solution:
x = -9/7
y = -26/7
In ordered pair form:
(-9/7,-26/7)
————— ————— —————
Hope this helps !!!!!!!
The answer is c ...use the distrubutive property to check it
Domain: -∞<x<∞
Range: -∞<x<∞
X-Intercept: x=0
Y-Intercept: y=0
Increasing on the interval of 0<x<∞
<span>Decreasing on the interval of -∞<x<0
</span>When A=0, the graph equals y=0
- When A is greater than 1, it makes the graph skinnier than <span>f(x)=|x|
- When A is less than 1 but greater than 0, it makes the graph fatter than </span><span>f(x)=|x|
- When A turns negative, it flips the graph upside down.
-When B is greater than 0, it translates the graph to the right
- When B is less than 0, it translates the graph to the left
When C is greater than 0, the graph moves upwards
When C is less than 0, the graph moves downwards</span>
Well let's see.
The equation has exactly one solution.
Hope this helps.
