Answer:
Amount of fencing required = 75 yards
Step-by-step explanation:
Distance between the two points
and
is given by the formula,
d = 
Distance between A(3, 6) and B(3, -2) = 
= 8 yards
Distance between B(3, -2) and C(-7, 4) = 
= 
= 11.66 ≈ 12 yards
Distance between C(-7, 4) and D(-7, -2) = 
= 6 yards
Distance between D(-7, -2) and E(-3, -2) = 
= 4 yards
Distance between E(-3, -2) and F(-3, -8) = 
= 6 yards
Distance between F(-3, -8) and G(3, -8) = 
= 6 yards
Distance between G(3, -8) and H(10, -12) = 
= 
= 
= 8.06 ≈ 8 yards
Distance between H(10, -12) and J(10, 6) = 
= 18 yards
Distance between A(3, 6) and J(10, 6) = 
= 7 yards
Since length of fence required = perimeter of the flat area
Perimeter of the given area = 8 + 12 + 6 + 4 + 6 + 6 + 8 + 18 + 7
= 75 yards
Therefore, amount of fencing required = 75 yards