Answer:
Explanation:
Expression for capillary rise is as follows
h = 2T / ρ g r where T is surface tension , ρ is density of liquid and r is radius of capillary tube.
T = .032 J m⁻²
ρ = .71 g / cm³
= 7100 kg / m³
r = .1 x 10⁻³ m = 10⁻⁴ m
h = 2 x .032 / (7100 x 9.8 x 10⁻⁴ )
h = .0092 m
= 9.2 mm .
Missing question: What is the rate constant for the reaction?
<span>[RS2](mol L-1) Rate (mol/(L·s))
0.150 0.0394
0.250 0.109
0.350 0.214
0.500 0.438</span>
Chemical reaction: 3RS₂ → 3R + 6S.
Compare second and fourth experiment, when concentration is doubled, rate of concentration is increaced by four. So rate is:
rate = k·[RS₂]².
k = 0,438 ÷ (0,500)².
k = 1,75 L/mol·s.
