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vovikov84 [41]
2 years ago
14

50 mL graduated cylinder contains 25.0 mL of water. A 142.5040 g piece of osmium is placed in the graduated cylinder and the wat

er level rises to 31.3 mL. What is the density of the piece of osmium?
Chemistry
1 answer:
GrogVix [38]2 years ago
8 0

Answer:

22.6g/mL

Explanation:

density = mass / volume

given mass of object : 142.5040

volume of object : not given however we are told that when placed inside of a cylinder with 25 mL of water the water level rises to 31.3 mL

31.3 - 25 = 6.3

So the water level rose by 6.3 mL meaning that the object has a volume of 6.3 mL

Now to find the density.

Recall that density = mass / volume

mass = 142.5040 g and volume = 6.3 mL

so density = 142.5040g / 6.3 mL = 22.6 g / ml

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3 years ago
A student is determining the density of an unknown metal with a mass of 32.56 g. The student partially fills a graduated cylinde
xenn [34]

Answer:

The metal is Tin (Sn)

Explanation:

The following data were obtained from the question:

Mass of metal = 32.56 g

Volume of water = 14.78 mL

Volume of water + metal = 20.44 mL

Next, we shall determine the volume of the metal. This is illustrated below:

Volume of water = 14.78 mL

Volume of water + metal = 20.44 mL

Volume of metal =..?

Volume of metal = (Volume of water + metal) – (Volume of water )

Volume of metal = 20.44 – 14.78

Volume of metal = 5.66mL

Next, we shall determine the density of the metal.

Density of a substance is defined as the mass of the substance per unit volume of the substance. Mathematically, the density of a substance is expressed as:

Density = Mass / volume

With the above formula, we can obtain the density of the metal as follow:

Mass of metal = 32.56 g

Volume of metal = 5.66mL

Density =.?

Density = Mass /volume

Density = 32.56g/5.66mL

Density of the metal = 5.75g/mL

Comparing the density of the metal with standard density of elements, the metal is Tin (Sn)

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3 years ago
What is the molar mass of C3N4? (Do NOT round this number.)
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Answer:

92.06 g/mol

Explanation:

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In carbon dioxide (CO2), how many grams of oxygen (O) would there be if there are 24 grams of carbon (C)?
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Answer:

64g of Oxygen

Explanation:

Firstly, carbon and oxygen react to form CO2 as follows;

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According to the equation, one mole of C reacts with one mole of O2 to give one mole of CO2

Since molar mass of C= 12g/mol, O= 16g/mol

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