Answer: option C) gather information and identify stakeholders
Explanation:
The sales, distribution and advertisement of alcoholic beverages requires information on consumer protection, health risks, and environmental factors. And Garrett would simply get such from the relevant stakeholders like regulatory agencies.
Thus, Garrett should first gather information and identify stakeholders
Answer:
The number 10,847,100 in Scientific Notation is 
Explanation:
Scientific notation is an easy form to write long numbers and it is commonly used in the scientific field. To write a long number in a shorter way it is necessary to 'move' the decimal point to the left the number of positions that are necessary until you get a unit. Then you write the number and multiplied it by 10 raised to the number of positions you moved the decimal point. In this case, it is necessary to move the decimal point 7 positions so, we multiply the number by 10 raised to 7.
Answer:
None of these cause the correct answer is 9/-5
Answer:
The mass of ammonia (NH3) that contains 
hydrogen atoms is 
g.
Explanation:
As 
atoms of hydrogen = 1 mole of the hydrogen atom
Therefore, 
atoms of hydrogen 
moles of the hydrogen atom.
Now, there are 3 moles of hydrogen atoms in 1 mole of ammonia 
.
As the mass of 1 mole of ammonia is 17g, so
when there are 3 moles of hydrogen atoms, then the mass of ammonia = 17 g
Therefore, when there are 
moles of hydrogen atoms, then the mass of ammonia 
g.
Hence, the mass of ammonia that contains hydrogen atoms is g.
Answer:
-3135.47 kJ/mol
Explanation:
Step 1: Write the balanced equation
C₆H₆(l) + 7.5 O₂(g) ⇒ 6 CO₂(g) + 3 H₂O(g)
Step 2: Calculate the standard enthalpy change of the reaction (ΔH°r)
We will use the following expression.
ΔH°r = ∑np × ΔH°f(p) - ∑nr × ΔH°f(r)
where,
n: moles
ΔH°f: standard enthalpies of formation
p: products
r: reactants
ΔH°r = 6 mol × ΔH°f(CO₂(g)) + 3 mol × ΔH°f(H₂O(g)) - 1 mol × ΔH°f(C₆H₆(l)) - 7.5 mol × ΔH°f(O₂(g))
ΔH°r = 6 mol × (-393.51 kJ/mol) + 3 mol × (-241.82 kJ/mol) - 1 mol × (48.95 kJ/mol) - 7.5 mol × 0 kJ/mol
ΔH°r = -3135.47 kJ
Since this enthalpy change is for 1 mole of C₆H₆(l), we can express it as -3135.47 kJ/mol.
