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PilotLPTM [1.2K]
4 years ago
13

Find the number of moles of butane (c4h10) in 21g sample of butane gas​

Chemistry
1 answer:
iogann1982 [59]4 years ago
8 0

Answer:

0.362 moles

Explanation:

Mass of butane = 21g

Molar mass of carbon = 12g / mol

Molar mass of hydrogen = 1g/mol

Molar mass of butane ? = [(12*4) * (1*10)]

Molar mass of butane = 58g / mole

Number of moles = mass of molecules / molar mass of molecule

Number of moles = 21 / 58

Number of moles of butane = 0.362 moles

The number of moles in 21g of butane is 0.362 moles

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vodka [1.7K]

Answer:

Explanation:

crystallization The crystallization temperature of a brine is the temperature at which a solid phase begins to form, resulting in a mixture of solid particles and solution. These solids may be salt crystals or water crystals (ice). It is the point at which the minimumcrystallization temperature can be realized

8 0
3 years ago
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A sample of gas has a pressure of 742 torr. What is the pressure in atmospheres?
ycow [4]

Answer:742 torr= approximately 0.976 atm

Explanation:

Since we know that one atm= 760 torr, we can compute the following calculation:

(742 torr/1)*(1atm/760torr)=0.976316 atm

Remember sig figs (3) to round it to 0.976 atm

\frac{742 torr}{1}*\frac{1 atm}{760 torr}=0.976316=0.976 atm

(torr cancels out and we're left with atm)

Hope this helps :)

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3 years ago
A beaker is best used for measuring
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liquids, it has the measurements in ml.

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3 years ago
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A 1.50 L buffer solution is 0.250 M in HF and 0.250 M in NaF. Calculate the pH of the solution after the addition of 0.100 moles
alexgriva [62]

Answer : The pH of the solution is, 3.41

Explanation :

First we have to calculate the moles of HF.

\text{Moles of HF}=\text{Concentration of HF}\times \text{Volume of solution}

\text{Moles of HF}=0.250M\times 1.50L=0.375mol

Now we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (6.8\times 10^{-4})

pK_a=4-\log (6.8)

pK_a=3.17

The reaction will be:

                             HF+OH^-\rightleftharpoons F^-+H_2O

Initial moles     0.375     0.100   0.375

At eqm.   (0.375-0.100)      0     (0.375+0.100)

                     = 0.275                    = 0.475

Now we have to calculate the pH of solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[F^-]}{[HF]}

Now put all the given values in this expression, we get:

pH=3.17+\log [\frac{(\frac{0.475}{1.50})}{(\frac{0.275}{1.50})}]

pH=3.41

Thus, the pH of the solution is, 3.41

8 0
3 years ago
Which substance is a mixture?<br> table salt<br> gasoline<br> aluminum<br> carbon dioxide
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