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3 years ago

Find the number of moles of butane (c4h10) in 21g sample of butane gas

Chemistry

1 answer:

iogann1982 [59]3 years ago

8 0

Answer:

0.362 moles

Explanation:

Mass of butane = 21g

Molar mass of carbon = 12g / mol

Molar mass of hydrogen = 1g/mol

Molar mass of butane ? = [(12*4) * (1*10)]

Molar mass of butane = 58g / mole

Number of moles = mass of molecules / molar mass of molecule

Number of moles = 21 / 58

Number of moles of butane = 0.362 moles

The number of moles in 21g of butane is 0.362 moles

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2 years ago

An electron in the hydrogen atom makes a transition from an energy state of principal quantum number ni to the n = 2 state. If t

topjm [15]

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$\boxed{3}$

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Calculation:

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2 years ago

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2 years ago

Read 2 more answers

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Kay [80]

Answer: 18.0152 milliliters

Explanation:

Hi, to answer this question we have to apply the next formula:

Water volume = water mass / water density

Since 1 mol of water weights 18.0152 grams

Replacing with the values and solving:

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3 years ago

What is the percent composition of hydrogen if a sample is found to contain 7 grams of hydrogen, 32 grams of nitrogen, and 7 gra

nata0808 [166]

<u>Answer:</u> The percent composition of hydrogen in the sample is 15.22 %

<u>Explanation:</u>

We are given:

Mass of hydrogen = 7 grams

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Mass of carbon = 7 grams

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To calculate the percentage composition of hydrogen in sample, we use the equation:

$\%\text{ composition of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of sample}}\times 100$

Mass of sample = 46 g

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Putting values in above equation, we get:

$\%\text{ composition of hydrogen}=\frac{7g}{46g}\times 100=15.22\%$

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3 years ago

Find the number of moles of butane (c4h10) in 21g sample of butane gas​

Find the number of moles of butane (c4h10) in 21g sample of butane gas