Question

Find the number of moles of butane (c4h10) in 21g sample of butane gas​

Answer 1

Answer:

0.362 moles

Explanation:

Mass of butane = 21g

Molar mass of carbon = 12g / mol

Molar mass of hydrogen = 1g/mol

Molar mass of butane ? = [(12*4) * (1*10)]

Molar mass of butane = 58g / mole

Number of moles = mass of molecules / molar mass of molecule

Number of moles = 21 / 58

Number of moles of butane = 0.362 moles

The number of moles in 21g of butane is 0.362 moles