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3 years ago

What is the solution to the inequality 2n+5 > 1

Mathematics

2 answers:

melomori [17]3 years ago

6 0

Solve this like a regular equation:

2n + 5 > 1
2n > -4
n > -2

Hope this helped!

Darina [25.2K]3 years ago

4 0

Answer:

The solution to the inequality $2n+5>1$ is; the set of solutions of the inequality is the interval i.e, $(-2 , \infty)$

Step-by-step explanation:

To find the solution of the inequality: $2n+5>1$

Subtraction property of equality states that you subtract the same number to both sides of an equation.

Subtract 5 to both sides of an equation, we get;

$2n+5-5>1-5$

Simplify:

$2n>-4$

Division property of equality states that you divide the same number to both sides of an equation.

Divide by 4 to both sides of an equation;

$\frac{2n}{2}>\frac{-4}{2}$

Simplify:

$n > -2$

All real numbers greater than -2 satisfy the inequality.

therefore, the set of solutions of the inequality is the interval $(-2 , \infty)$

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3 years ago

Are your finances, buying habits, medical records, and phone calls really private? A real concern for many adults is that comput

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Answer:

a)There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

b)There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

c)There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

Step-by-step explanation:

The binomial probability is the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes (commonly called a binomial experiment).

It is given by the following formula:

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of a success.

In this problem, a success is being concerned that employers are monitoring phone calls.

53% of adults are concerned that employers are monitoring phone calls, so $p = 0.53$

(a) Out of four adults, none is concerned that employers are monitoring phone calls.

Four adults, so $n = 4$ .

Is the probability of 0 successes, so x = 0.

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

$P = C_{4,0}.(0.53)^{0}.(0.47)^{4}$

$P = 0.0488$

There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

(b) Out of four adults, all are concerned that employers are monitoring phone calls.

Four adults, so $n = 4$ .

Is the probability of 4 successes, so x = 4.

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

$P = C_{4,0}.(0.53)^{4}.(0.47)^{0}$

$P = 0.0789$

There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

(c) Out of four adults, exactly two are concerned that employers are monitoring phone calls.

Four adults, so $n = 4$ .

Is the probability of 4 successes, so x = 2.

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

$P = C_{4,2}.(0.53)^{2}.(0.47)^{2}$

$P = 0.3723$

There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

3 0

3 years ago