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2 years ago

Solve for x.7x+ 33x + 35x = [?]

Mathematics

1 answer:

Dafna11 [192]2 years ago

4 0

Answer:

Step-by-step explanation:

7x + 3 = 3x + 35

4x + 3 = 35

4x = 32

x = 8

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5/4q = 1/3 -2/3 + 2 help please

KengaRu [80]

Answer:

q=4/3

Step-by-step explanation:

simplify the right side, to 5/3

5/4q=5/3

multiply 4/5 on both sides

q = 5/3*4/5

q = 4/3

4 0

1 year ago

Find the slope-intercept form of the given line that passes through the points (0, -3) and (4, 1). Include your work in your fin

Rus_ich [418]

The slope-intercept of a line is expressed as y=mx + b where m is the slope which is equal to change in y over change in x and b is the y-intercept. We can obtain this form from two points by doing as follows:

y - y1 = m(x-x1)
y + 3 = (1 + 3) / (4-0) (x - 0)
y + 3 = x
y = x -3

where m is 1 and b is -3

8 0

2 years ago

3x3 1/7 which two whole number

pishuonlain [190]

Could you explain a bit more please

7 0

2 years ago

Read 2 more answers

(X^4)-(45x^2)+324 what are the zeroes? And how many turning points?

dmitriy555 [2]

Zeroes:

We must solve

$x^4-45x^2+324=0$

To do so, we define the auxiliary variable $t=x^2$ . The equation becomes

$t^2-45t+324=0$

The quadratic formula yields the solutions

$t=9,\quad t=36$

Substituting back $t=x^2$ gives

$x^2=9 \iff x=\pm 3,\quad x^2=36 \iff x=\pm 6$

So, the zeroes are -6, -3, 3, 6.

Turning points:

Turning points are points where a function stops being increasing to become decreasing, or vice versa. Since functions are increasing when their first derivative is positive and decreasing when it's negative, turning points are points where the first derivative is zero.

We have

$f(x)=x^4-45x^2+324 \implies f'(x)=4x^3-90x$