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BartSMP [9]
3 years ago
7

What is the taxidistance between (2,11) and (7,10) 4 6 7 26

Mathematics
1 answer:
Scilla [17]3 years ago
4 0
X difference: 7-2 = 5 y difference: 11-10 = 1 Add up those results: 5+1 = 6 

Answer Is 6
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Make -7-15 into a equivalent addition problem
Greeley [361]

The value -7-15  into a equivalent addition problem is  -7+(-15)  

<h3>Sum of values</h3>

Given the given expression

-7-15

We are to make it into equivalent addition as shown;

-7-15)  = -7+(-15)

Since the product of a positive ad negative sign is equivalent to negative, hence the expression will become;

-7-15  = -7+(-15)

-7-15  = -22

Hence the value -7-15  into a equivalent addition problem is  -7+(-15)  

Learn more on equation here:  brainly.com/question/2972832

#SPJ1

8 0
1 year ago
There were 407 boys and 438 girls who like to join the Independence Day parade. How many buses will be hired if 65 persons can b
AURORKA [14]

Answer:

13

Step-by-step explanation:

just add them both and divide by 65

4 0
3 years ago
Read 2 more answers
What are the values that satisfy the trigonometric equation for: 0 ≤ q ≤ 2Π ?
bagirrra123 [75]
Answer: 0, π, 2π

Nevertheless, that is not an option. I see two possibilities: 1) the options are misswirtten, 2) the domain is not well defined.

If the domain were 0 ≤ θ < 2π, then 2π were excluded of the domain ant the answer would be 0, π.

Explanation:

1) The first solution, θ = 0 is trivial:

sin (0) - tan (0) = 0

0 - 0 = 0

2) For other solutions, work the expression:

sin(θ) + tan (-θ) = 0 ← given

sin (θ) - tan(θ) = 0 ← tan (-θ) = tan(θ)

sin(θ) - sin (θ) / cos(θ) = 0 ← tan(θ) = sin(θ) / cos(θ)

sin (θ) [1 - 1/cos(θ)] = 0 ← common factor sin(θ)

⇒ Any of the two factors can be 0

⇒ sin (θ) = 0 or (1 - 1 / cos(θ) = 0,

sin(θ) = 0 ⇒ θ = 0, π, 2π

1 - 1/cos(θ) = 0 ⇒ 1/cos(θ) = 1 ⇒ cos(θ) = 1 ⇒ θ = 0, 2π

⇒ Solutions are 0, π, and 2π

In fact if you test with any of those values the equation is checked. The only way to exclude one of those solutions is changing the domain.
7 0
3 years ago
Read 2 more answers
Geoffrey is evaluating the expression (-3^3(2^6)/(-3^5(2^2) what are the values of a,b,c and d
tiny-mole [99]
-9×36÷-15×4
-324÷60
-5.4
(not sure if this is what you are looking for)
5 0
3 years ago
Express as a trinomial: (2x-3)(x 5)
Illusion [34]
I am assuming the expression is (2x-3)(x+5) or (2x-3)(x-5). I will teach you how to solve for both as I am not sure which one you are asking for. There are 4 steps to multiplying.

1) Multiply the x times the second x
2) Multiply x times the second number
3) Multiply the number by the second x
4) Multiply the number by the second number.

(2x*x)+(2x*5)+(-3*x)+(-3*5)=(2x^{2})+(10x)+(-3x)+(-15)=2x^{2}+7x-15

(2x*x)+(2x*-5)+(-3*x)+(-3*-5)=(2x^{2})+(-10x)+(-3x)+(15)=2x^{2}-13x+15

Your answer is 2x^{2}+7x-15 or 2x^{2}-13x+15. Does that answer your question?
6 0
3 years ago
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