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3 years ago

11

The distance on a map between Lake Village And bay Cove is 2 in if 1 inch represents 15 miles what is the actual distance betwee

n Lake Village and bay cove

1 answer:

Genrish500 [490]3 years ago

5 0

Just multiply 2 and 15 and you get 30. 30 miles is the answer

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storchak [24]

The value of d is -2

Step-by-step explanation:

The nth term of the arithmetic sequence is $u_{n}=u_{1}+(n-1)d$ , where

$u_{1}$ is the first term
d is the common difference between each 2 consecutive terms

The nth term of the geometric sequence is $u_{n}=u_{1}r^{n-1}$ , where

$u_{1}$ is the first term
r is the common ratio between each two consecutive terms $r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}$

∵ $u_{1}$ of an arithmetic sequence is 1

∵ The common difference is d, where d ≠ 0

∵ $u_{2}$ , $u_{3}$ , $u_{6}$ are the first 3 terms of a geometric sequence

∵ $u_{2}$ = 1 + (2 - 1)d

∴ $u_{2}$ = 1 + d

∵ $u_{3}$ = 1 + (3 - 1)d

∴ $u_{2}$ = 1 + 2d

∵ $u_{6}$ = 1 + (6 - 1)d

∴ $u_{2}$ = 1 + 5d

∴ The first 3 terms of the geometric sequence are (1 + d) , (1 + 2d) ,

(1 + 5d)

∵ The common ratio in the geometric sequence is $r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}$

∴ $r=\frac{1+2d}{1+d}=\frac{1+5d}{1+2d}$

- Use cross multiplication with the equal fractions

∵ $\frac{1+2d}{1+d}=\frac{1+5d}{1+2d}$

∴ (1 + 2d)(1 + 2d) = (1 + d)(1 + 5d)

∴ 1 + 2d + 2d + 4d² = 1 + 5d + d + 5d²

- Add like terms in each side

∴ 1 + 4d + 4d² = 1 + 6d + 5d²

- Subtract 1 from both sides

∴ 4d + 4d² = 6d + 5d²

- Subtract 4d from both sides

∴ 4d² = 2d + 5d²

- Subtract 4d² from each side

∴ 0 = 2d + d²

- Take d as a common factor

∴ 0 = d(2 + d)

- Equate each factor by 0

∴ d = 0 but we will reject it because d ≠ 0

∴ 2 + d = 0

- Subtract 2 from both sides

∴ d = -2

The value of d is -2

Learn more:

You can learn more about the sequence in brainly.com/question/1522572

#LearnwithBrainly

7 0

3 years ago

Which is a solution to the equation?<br> (х-2)(х + 5) = 18?

jok3333 [9.3K]

$\bf (x-2)(x+5)=18\implies \stackrel{\mathbb{F~O~I~L}}{x^2+3x-10}=18\implies x^2+3x-28=0 \\\\\\ (x-4)(x+7)=0\implies x= \begin{cases} 4\\ -7 \end{cases}$

4 0

3 years ago

How much less would a 23-year-old female pay for a $25,000 policy of 20 year life insurance (@ $2.90 per $1000) than straight li

mojhsa [17]

<u>Answer</u>:

The female would pay $322.00 less for a policy of $25,000

<u>Step-by-step explanation:</u>

Since we have given that

Amount for policy = $25000

If she opt for 20 year life insurance at $2.90 per $1000.

so, her amount of premium becomes

$25000\times \frac{2.9}{1000}$

=$72.50

If she opt for straight life insurance at $15.78 per $1000,

Then, her amount of premium becomes

$25000 \times \frac{15.78}{1000}$

= $394.50

Difference between them is given by

$394.50-$72.5 = $322.00

5 0

4 years ago

Read 2 more answers

Find the value of 5 ∙ 23.<br><br><br>30<br><br>40<<br><br>1,000

Mashutka [201]

Answer: 5 * 23 = 115 so 40<

Step-by-step explanation:

4 0

3 years ago

Solve the system: <br> 2/x - 3/y =-5; 4/x + 6\y =14

sertanlavr [38]

The solution is $x = 2 \text{ and } y = \frac{1}{2}$

<em><u>Solution:</u></em>

Let us assume,

$a = \frac{1}{x}\\\\b = \frac{1}{y}$

<em><u>Given system of equations are:</u></em>

$\frac{2}{x} - \frac{3}{y} = -5$

$\frac{4}{x} + \frac{6}{y} = 14$

<em><u>Rewrite the equation using "a" and "b"</u></em>

2a - 3b = -5 ------------ eqn 1

4a + 6b = 14 -------------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Multiply eqn 1 by 2</u></em>

2(2a - 3b = -5)

4a - 6b = -10 ------------- eqn 3

<em><u>Add eqn 2 and eqn 3</u></em>

4a + 6b = 14

4a - 6b = -10

( - ) --------------------

8a = 4

$a = \frac{4}{8}\\\\a = \frac{1}{2}$

Substitute a = 1/2 in eqn 1

$2(\frac{1}{2}) -3b = -5\\\\1 - 3b = -5\\\\3b = 6\\\\b = 2$

Now let us go back to our assumed values

Substitute a = 1/2 in assumed values

$a = \frac{1}{x}\\\\\frac{1}{2} = \frac{1}{x}\\\\x = 2$

Substitute b = 2 in assumed value

$b = \frac{1}{y}\\\\2 = \frac{1}{y}\\\\y = \frac{1}{2}$

Thus the solution is $x = 2 \text{ and } y = \frac{1}{2}$

3 0

3 years ago