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almond37 [142]
3 years ago
8

PLEASE HELP ME..........

Mathematics
1 answer:
Dima020 [189]3 years ago
3 0

Answer:

34.5?

Step-by-step explanation:

Grab 75 and subtract 6 from it. After that you divide 69 (the answer of 75-6) by 2. You then get 34.5

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What is the sum of 7/6 and 5/8
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1 19/24

Step-by-step explanation:

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PLZ HELP WILL GIVE BRAINLIEST!!!!!!!
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Anyone could be chosen but the highest possibility of chosen marble is red due to the percentage of marbles in bag being red.
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In one grade of 150 students, the ratio of boys to girls is 2 : 3.
Radda [10]

Answer:

60 boys are in the grade.

Step-by-step explanation: Since there are 150 students, we can divide that number by the combined ratio, which in this case is 5. Dividing 150 by 5 would yield 30 students. We can use this information to multiply the given number of boys in the ratio by 30, which would produce 60.

3 0
3 years ago
Can you please help meeee
Sidana [21]
3. y=5x+1
y=3x+5
5x+1=3x+5
5x-3x=5-1
2x=4
x=2

4.y=3x-5
3x-2y=4
2y=6x-10
2y=3x-4
6x-10=3x-4
6x-3x=-4+10
3x=6
x=2

5.3x-y=13
2x+3y=16
3x-y=13
2x+3y=16
y=3x-13
3y=16-2x
3y=9x-39
3y=16-2x
9x-39=16-2x
9x+2x=16+39
11x=55
x=11


Hope i helped ❤️
5 0
3 years ago
What is the common denominator of (5/x^2-4) - (2/x+2) in the complex fraction (2/x-2) - (3/x^2-4)/(5/x^2-4) - (2/x+2)
PIT_PIT [208]

9514 1404 393

Answer:

  • common denominator: (x² -4)
  • simplified complex fraction: (2x +1)/(9 -2x)

Step-by-step explanation:

It is helpful to remember the factoring of the difference of squares:

  a² -b² = (a -b)(a +b)

__

Your denominator of (x² -4) factors as (x -2)(x +2). You will note that one of these factors is the same as the denominator in the other fraction.

It looks like you want to simplify ...

  \dfrac{\left(\dfrac{2}{x-2}-\dfrac{3}{x^2-4}\right)}{\left(\dfrac{5}{x^2-4}-\dfrac{2}{x+2}\right)}=\dfrac{\left(\dfrac{2(x+2)}{(x-2)(x+2)}-\dfrac{3}{(x-2)(x+2)}\right)}{\left(\dfrac{5}{(x-2)(x+2)}-\dfrac{2(x-2)}{(x-2)(x+2)}\right)}\\\\=\dfrac{2(x+2)-3}{5-2(x-2)}=\boxed{\dfrac{2x+1}{9-2x}}

3 0
3 years ago
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