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____ [38]
3 years ago
14

Describe a pattern in each sequence. what are the next two terms of each sequence ? 2,4,8,16​

Mathematics
1 answer:
yan [13]3 years ago
8 0

Answer:

You are mulitplying the last number by two. The next two terms are 32 and 64.

Step-by-step explanation:

You might be interested in
Is -7-5+3=1 true or false
grigory [225]
-7-5+3=1
-12+3=1
-9≠1. As a result, this is False. Hope it help!
7 0
3 years ago
A certain city's population is 120,000 and decreases 1.4% per year for 15 years.
mart [117]

Answer:

  • Decay Problem.
  • Decay rate,  r = 0.014
  • Initial Amount =120,000
  • P(t)=120000(0.986)^t
  • P(10)=104,220

Step-by-step explanation:

The exponential function for growth/decay is given as:

P(t)=P_0(1 \pm r)^t, where:\\P_0$ is the Initial Population\\r is the growth/decay rate\\t is time

In this problem:

The city's initial population is 120,000 and it decreases by 1.4% per year.

  • Since the population decreases, it is a Decay Problem.
  • Decay rate, r=1.4% =0.014
  • Initial Amount =120,000

Therefore, the function is:

P(t)=120000(1 - 0.014)^t\\P(t)=120000(0.986)^t

When t=10 years

P(10)=120000(0.986)^10\\=104219.8\\\approx 104220 $ (to the nearest whole number)

8 0
3 years ago
Please help
vagabundo [1.1K]
I would say no to that.
4 0
3 years ago
3/4 part of a rope is 150m. find the length of 7/10 part of the rope
a_sh-v [17]

Answer:

140m

Step-by-step explanation:

3/4 = .75

x/.7 = 150/.75

multiply both sides by .7

x = 150/.75 * .7

x = 140m

6 0
3 years ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
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