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tester [92]
3 years ago
13

Line m passes through the points (-2, 12) and (5, – 3). Which is the slope of a

Mathematics
1 answer:
schepotkina [342]3 years ago
8 0

Answer:

the dog

Step-by-step explanation:

dfg

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(07.03 LC) The steps below show the incomplete solution to find the value of q for the equation 4q − 2q − 4 = −1 + 21: Step 1: 4
Elza [17]

Answer:

3: 2q − 4 = 20

Step-by-step explanation:

Solve for q:

2 q - 4 = 20

Add 4 to both sides:

2 q + (4 - 4) = 4 + 20

4 - 4 = 0:

2 q = 20 + 4

20 + 4 = 24:

2 q = 24

Divide both sides of 2 q = 24 by 2:

(2 q)/2 = 24/2

2/2 = 1:

q = 24/2

The gcd of 24 and 2 is 2, so 24/2 = (2×12)/(2×1) = 2/2×12 = 12:

Answer:  q = 12

8 0
3 years ago
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Heather opens a bank account with $125. Each week, starting the following week, she deposits $25 into her account.
Rufina [12.5K]
Total money in account=125+25n
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4 years ago
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There are 4 triangles and 20 squares what is the simplest ratio of triangles to squares
Svetllana [295]

Answer: 4:20 but that simplified would be 1:5

Triangles to squares

8 0
3 years ago
The ratio of green pepper plants to red pepper plants in Joe's garden is 2:7. If Joe has 20 more red pepper plants than green pe
Marta_Voda [28]
I found that Joe has 28 red pepper plants and 8 green pepper plants.

to find this, I first set up a proportion:
7/2 = (20+x)/x

then you cross multiply giving you:
7x = 40 + 2x

Subtract 2x from both sides:
5x = 40

solve for x:
x = 8 (which is the amount of green pepper plants)

to find how many red pepper plants he has, plug in x for (20 + x) giving you 28 red pepper plants

Hope I helped :)
5 0
3 years ago
Verify that this trigonometric equation is an identity?
Vlada [557]
\cot x\sec^4 x=\cot x+2\tan x+\tan^3x\\\\L=\dfrac{\cos x}{\sin x}\cdot\dfrac{1}{\cos^4x}=\dfrac{1}{\sin x}\cdot\dfrac{1}{\cos^3x}=\dfrac{1}{\sin x\cos^3x}\\\\R=\dfrac{\cos x}{\sin x}+2\cdot\dfrac{\sin x}{\cos x}+\dfrac{\sin^3x}{\cos^3x}\\\\=\dfrac{\cos x\cos^3x}{\sin x\cos^3x}+\dfrac{2\sin x\cos^2x}{\cos x\sin x\cos^2x}+\dfrac{\sin^3x\sin x}{\cos^3x\sin x}\\\\=\dfrac{\cos^4x+2\sin^2x\cos^2x+\sin^4x}{\sin x\cos^3x}\\\\=\dfrac{(\cos^2x)^2+2\sin^2x\cos^2x+(\sin^2x)^2}{\sin x\cos^3x}

=\dfrac{(\cos^2x+\sin^2x)^2}{\sin x\cos^3x}=\dfrac{1}{\sin x\cos^3x}=L\\\\Used:\\\tan(a)=\dfrac{\sin(a)}{\cos(a)}\\\cot(a)=\dfrac{\cos(a)}{\sin(a)}\\\sec(a)=\dfrac{1}{\cos(a)}\\\sin^2a+\cos^2a=1\\(a+b)^2=a^2+2ab+b^2
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4 years ago
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