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Papessa [141]
4 years ago
7

BC¯¯¯¯¯ is parallel to DE¯¯¯¯¯.

Mathematics
2 answers:
pentagon [3]4 years ago
8 0

∆ABC ~ ∆ADE

AC/AE = AB/AD

AC = AE•AB/AD

AC = (AC + 15)•8/18

9AC = 4AC + 60

5AC = 60

AC = 12

Fantom [35]4 years ago
8 0

Answer:

AC = 12

Step-by-step explanation:

We can use proportions to solve.  Put the smaller triangle side over the larger triangle side

AB           AC

--------- = --------

AD          AE

Substituting what we know

8            AC

--------- = --------

8+10          AC+15

Using cross products

8 *(AC+15) = (8+10)*AC

Simplify

8 *(AC+15) = (18)*AC

Distribute

8AC +120 = 18AC

Subtract 8AC from each side

8AC-8AC +120 = 18AC -8AC

120 =10AC

Divide each side by 10

120/10 = 10AC/10

12=AC

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