Wild guess?
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It will be whichever equation you see that has the "c" = +3, in the format:
F(x) = y = ax^2 + bx + c, where a, b, and c are all integers, such that plugging a "0" into the x's will give:
y = a•0^2 + b•0 + 3 = 0 + 0 + 3 = 3
Step-by-step explanation:
The center of a circle with 2 end points of a di diameter is the midpoint of the two endpoints.
The formula needed to find the minpoints is
(x,y) = (x2 + x1)/2, (y2 + y1)/2
x2 = 3
x1 = 3
y2 = 0
y1 = -7
midpoint = (3 + 3)/2, (0 - 7)/2
midp[oint = 3,-3.5
The midpoint is the center of the circle. Observe that the signs get changed when entering the values for (x,y)
So far what you have is (x - 3)^2 + (y + 3.5)^2 = r^2
To determine r^2 you need only take the distance from the center to oneof the endpoints.
r^2 = (3 - 3)^2 + (3.5 - 0)^2
r^2 = 3.5^2
r^2 = 12.25
Answer: (x - 3)^2 + (y + 3.5)^2 = 12.25
Answer:
A. 3
B. 3/4
C. 1/4
Step-by-step explanation:
1/4 of 12 is 3
3 plus 6 is 9 and 9 is 3/4 of 12
12 minus nine is also three leaving the tank still a 1/4 tank empty
