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ANTONII [103]
3 years ago
9

3. Which of these paste options is commonly available from the Paste Options button? A. Paste as content only B. Use the destina

tion theme C. Keep the embedded data formatting D. A combination of integrating and embedding
Computers and Technology
1 answer:
Murljashka [212]3 years ago
7 0
In my experience, the correct answer is C) Keep the embedded data formatting. This is because it makes the computer do less work.

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You can earn ranks! That is important.
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For this exercise, you are going to create a part of an Animal hierarchy. Unlike some of our examples and the previous exercises
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vehicle super class 9.1.4

Explanation:

So you need to create a super class containig all the animals use the class above for referance

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3 years ago
A personal identification number (PIN) that opens a certain lock consists of a sequence of 3 different digits from 0 through 9,
Elan Coil [88]

Answer:

<u>720</u> possible PIN can be generated.

Explanation:

To calculate different number of orders of digits to create password and PIN, we calculate permutation.

Permutation is a term that means the number of methods or ways in which different numbers, alphabets, characters and objects can arranged or organized. To calculate the permutation following formula will be used:

nPr = n!/(n-r)!

there P is permutation, n is number of digits that need to be organize, r is the size of subset (Number of digits a password contains)

So in question we need to calculate

P=?

where

n= 10   (0-9 means total 10 digits)

r= 3     (PIN Consist of three digits)

So by using formula

10P3 = 10!/(10-3)!

        =10!/7!

        = 10x9x8x7!/7!

        = 10x9x8

        = 720

7 0
3 years ago
Whenever you are designing a project for commercial use (making money) and need to use photographs with people in them you must
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Copyright

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7 0
3 years ago
A teacher has five students who have taken four tests. The teacher uses the following grading scale to assign a letter grade to
AlladinOne [14]

Answer:

#include <iostream>

using namespace std;

int main()

{

const int numofStudents = 5;//number of students

const int numofTests = 2;//number of tests taken by students

const int grade = 5;//number of grades available

char letter[grade] = { 'A','B','C','D','F' };

double table[numofStudents][numofTests];//defining 2darray with names and scores

string names[numofStudents];//storing names of students

for (int num = 0; num < numofStudents; num++)//storing names and scores of students

{

 cout << "Enter student's name: ";

 cin >> names[num];

 for (int test = 0; test < numofTests; test++)//scores loop

 {

  cout << "Enter the test score: ";

  cin >> table[num][test];

  if (table[num][test] < 0 || table[num][test]>100)//input validation

  {

   cout << "Invalid input. Try again" << endl;

   cin >> table[num][test];//input again

  }

 }

}

for (int i = 0;i < numofStudents;i++)//calculating averages and grades

{

 int sum = 0;

 cout << "Test scores for " << names[i] << ": " << endl;

 for (int j = 0;j < numofTests;j++)

 {

  cout << table[i][j] << " ";

  sum += table[i][j];//summing scores

 }

 cout << endl;

 float average = (float)sum / numofTests;//calculating the average

 cout << "Making an average of: "<< average;

 if (average <= 100 && average >= 90)//assigning a grade

 {

  cout << " and has received an " << letter[0];

 }

 else if (average <= 89 && average >= 80)

 {

  cout << " and has received a " << letter[1];

 }

 else if (average <= 79 && average >= 70)

 {

  cout << " and has received a " << letter[2];

 }

 else if (average <= 69 && average >= 60)

 {

  cout << " and has received a " << letter[3];

 }

 else if (average <= 59 && average >= 0)

 {

  cout << " and has received an " << letter[4];

 }

 else

 {

  cout << "Invalid scores entered." << endl;

 }

 cout << endl;

}

 return 0;

}

Explanation:

We first define the number of students, number of tests and number of grades available for assignments. We then fill in the 2D array of students names and their scores making sure assigning more than 100 and less than 0 is not allowed. We then sum the scores and retrieve an average. Using the average, a letter grade is assigned to that individual.

6 0
3 years ago
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