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TEA [102]
3 years ago
10

Naomi can run 1/4 mile in 2 minutes. Does Amal or Naomi run faster? How do you know

Mathematics
1 answer:
telo118 [61]3 years ago
4 0

Answer: Yes

Step-by-step explanation:

A: 12 minutesAnswer to B: 36 minutesAnswer to C:

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A deck of cards contains RED cards numbered 1,2,3 and BLUE cards numbered 1,2,3,4,5,6. Let R be the event of drawing a red card,
Tatiana [17]

Answer:

e. R′

Step-by-step explanation:

Let the Sample Space be a universal set consisting of 3 red  and 6 blue cards. Then the event of  of getting 4 blue cards will be given

R complement = R` = Universal Set minus Red cards will give blue cards.

a. R OR O

It cannot be this option because we need 4 blue card

b. B AND O

It cannot be this choice as well because 4 is not odd.

c. R OR E

4 is even but we need blue

d. R AND O

Red and odd is again not required

e. R′  = It  will give our required result.

f. E′= 4 is even if it is complemented it cannot be obtained and will be left out.

5 0
4 years ago
What is an end point of a ray
Slav-nsk [51]

Answer:

The end point of a ray is A

Step-by-step explanation:

Hope this Helps

5 0
3 years ago
How to factor y= x^3-x^3-3x when the answer is y=(x-1)(x^2+3)
riadik2000 [5.3K]

Answer:

R u in geometry 1?

Step-by-step explanation:

4 0
3 years ago
20x+32y=0 <br> -50x-80y=0
german

Answer:

dont know what you need

Step-by-step explanation:

explain what you need

4 0
3 years ago
Calculate the flux of the vector field F⃗ (x,y,z)=(exy+9z+4)i⃗ +(exy+4z+9)j⃗ +(9z+exy)k⃗ through the square of side length 3 wit
ikadub [295]

The square (call it S) has one vertex at the origin (0, 0, 0) and one edge on the y-axis, which tells us another vertex is (0, 3, 0). The normal vector to the plane is \vec n=\vec\imath-\vec k, which is enough information to figure out the equation of the plane containing S:

(x\,\vec\imath+y\,\vec\jmath+z\,\vec k)\cdot(\vec\imath-\vec k)=0\implies x-z=0\implies z=x

We can parameterize this surface by

\vec s(x,y)=x\,\vec\imath+y\,\vec\jmath+x\,\vec k

for 0\le x\le\frac3{\sqrt2} and 0\le y\le3. Then the flux of \vec F, assumed to be

\vec F(x,y,z)=(e^{xy}+9z+4)\,\vec\imath+(e^{xy}+4z+9)\,\vec\jmath+(9ze^{xy})\,\vec k,

is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\iint_S\vec F(\vec s(x,y))\cdot\vec n\,\mathrm dx\,\mathrm dy

=\displaystyle\int_0^3\int_0^{3/\sqrt2}\left((4+e^{xy}+9x)\,\vec\imath+(9+e^{xy}+4x)\,\vec\jmath+(e^{xy}+9x)\,\vec k\right)\cdot(\vec\imath-\vec k)\,\mathrm dx\,\mathrm dy

=\displaystyle\int_0^3\int_0^{3/\sqrt2}4\,\mathrm dx\,\mathrm dy=\boxed{18\sqrt2}

3 0
3 years ago
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