Question

What is the mass of 3.8 × 10^24 atoms of argon (ar)? 0.0039 g 0.16 g 6.3 g 250 g

Answer 1

Atomic mass Ar => 39.948 a.m.u

39.948 g --------------- 6.02x10²³ atoms
?? g -------------------- 3.8x10²⁴ atoms

(3.8x10²⁴) x 39.948 / 6.02x10²³ => 250 g

hope this helps!

Answer 2

Answer : The mass of argon will be, 250 grams

Explanation : Given,

Number of atoms of argon = $3.8\times 10^{24}$

As we know that, 1 mole of substance contains $6.022\times 10^{23}$ number of atoms.

First we have to calculate the moles of argon.

As, $6.022\times 10^{23}$ number of argon atoms present in 1 mole of argon

So, $3.8\times 10^{24}$ number of argon atoms present in $\frac{3.8\times 10^{24}}{6.022\times 10^{23}}=6.31$ mole of argon

The moles of argon = 6.31 mole

Now we have to calculate the mass of argon.

$\text{Mass of }Ar=\text{Moles of }Ar\times \text{Molar mass of }Ar$

$\text{Mass of }Ar=(6.31mole)\times (40g/mole)=252.4g$

The mass of argon = 252.4 grams that is approximately equal to 250 grams.

Therefore, the mass of argon will be, 250 grams.