Answer:
units.
Step-by-step explanation:
We have been given that two legs of triangle ABC measures 5 units each. We are asked to find the length of the hypotenuse.
We will use Pythagoras theorem to solve for the hypotenuse of triangle ABC.

Substituting our given values in above equation we will get,



Upon taking square root of both sides of our equation we will get,



Therefore, the length of hypotenuse of triangle ABC is
units.
For this case the first thing we must observe is that the mass increases 0.4 grams when the diameter increases 1 millimeter.
Therefore, the slope of the line is given by:
m = 0.4
Thus, the function that best suits the table is given by:
f (x) = -4 + 0.4x
For example, for x = 20 we have:
f (20) = -4 + 0.4 (20)
f (20) = -4 + 8
f (20) = 4
The result, matches the table.
Answer:
The function that is best represented by the scatter plot is:
f (x) = -4 + 0.4x
Answer:
Using a formula, the standard error is: 0.052
Using bootstrap, the standard error is: 0.050
Comparison:
The calculated standard error using the formula is greater than the standard error using bootstrap
Step-by-step explanation:
Given
Sample A Sample B


Solving (a): Standard error using formula
First, calculate the proportion of A



The proportion of B



The standard error is:







Solving (a): Standard error using bootstrapping.
Following the below steps.
- Open Statkey
- Under Randomization Hypothesis Tests, select Test for Difference in Proportions
- Click on Edit data, enter the appropriate data
- Click on ok to generate samples
- Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>
From the randomization sample, we have:
Sample A Sample B



So, we have:






Answer:
17% i think
Step-by-step explanation:
Domain is the set of numbers you can use
usually, domain=all real numbers except those that divide by zero
so find those exceptions
find what numbers make deonenator equal to 0 and exclude them
x-23 is denom
x-23=0
x=23
doman is all real numbers except 23