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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics

2 answers:

ollegr [7]3 years ago

7 0

An apple about to fall from a tree branch. The apple has a gravitational pull, while having potential energy at the same time.

qaws [65]3 years ago

5 0

GPE = mgh

So we are looking for an answer with a height involved with it:

A bicycle moving horizontally has no height above earth's surface (assuming earth's surface is our 0 reference point), so therefore it has no GPE. It would have KE however.

A horse slowing down from a run: no mention of height so therefore no GPE, KE however is present

A beaker sitting on the floor has no KE or GPE.

So an apple about to fall from a tree branch is the best example of GPE because a tree branch usually has a height to it meaning that GPE is present.

You might be interested in

4. Define resistance and describe what would happen to a light bulb if the voltage increased but the resistance stayed the same.

Arlecino [84]

Current would increase proportionally to voltage. Power dissipation (heating) would increase with the square of the voltage. And resistance means, "the refusal to accept or comply with something"

4 0

3 years ago

How long was a 60 W light bulb turned on if it used a total of 580 J of energy?

icang [17]

Here's the tool you need. You can't answer the question without this:

   "1 watt"
means
   "1 joule of energy, generated, used, or moved, every second".

So 60 watts = 60 joules per second

   Total energy generated,
      used, or moved = (power) x (time).

   580 joules = (60 watts) x (time)

Divide each side
by (60 watts): Time = (580 joules) / (60 joules/sec)

   = (9 and 2/3) seconds .

7 0

3 years ago

Two charges separated by 1 m exert 1 N forces on each other. If the charges are pushed to 1/4m separation, the force on each cha

Sloan [31]

Answer:

The force on each charge = 16 N

Explanation:

From coulombs law,

F = 1/4πε₀(q₁q₂)/d²........................ Equation 1

q₁q₂ = F4πε₀d²...................... Equation 2

Where F = force on the two charges, q₁ = charge on the first body, q₂ = charge on the second body, d = distance of separation, 1/4πε₀ = constant of proportionality.

When d = 1 m, F = 1 N,

Constant: 1/4πε₀ = 9×10⁹ Nm²/C²

Substituting these values into equation 2,

q₁q₂ = 1×1²/9×10⁹

q₁q₂ = 1/9×10⁹ C²

When d = 1/4 m, q₁q₂ = 1/9×10⁹ C² and 1/4πε₀ = 9×10⁹ Nm²/C²

Substituting these values into equation 1

F = 9×10⁹×1/9×10⁹ /(1/4)²

F = 1/(1/16)

F = 16 N

Therefore the force on each charge = 16 N

4 0

4 years ago

Time shifting occurs when _______.

Svet_ta [14]

The answer is C, individuals copy works to view at a later time.

4 0

4 years ago

Read 2 more answers

Two loudspeakers in a 20c room emit 686 hz sound waves along the x-axis.a. if the speakers are in phase, what is the smallest di

jeyben [28]

Answer :

(a) d = 0.25 m

(b) d = 0.5 m

Explanation :

It is given that,

Frequency of sound waves, f = 686 Hz

Speed of sound wave at $20^0\ C$ is, v = 343 m/s

(1) Perfectly destructive interference occurs when the path difference is half integral multiple of wavelength i.e.

$d=\dfrac{\lambda}{2}$ ........(1)

Velocity of sound wave is given by :

$v=f\times \lambda$

$d=\dfrac{v}{2f}$

$d=\dfrac{343\ m/s}{2\times 686\ Hz}$

$d=0.25\ m$

Hence, when the speakers are in phase the smallest distance between the speakers for which the interference of the sound waves is perfectly destructive is 0.25 m.

(2) For constructive interference, the path difference is integral multiple of wavelengths i.e.

$d=n\lambda$ ( n = integers )

Let n = 1

So, $d=\dfrac{v}{f}$

$d=\dfrac{343\ m/s}{686\ Hz}$

$d=0.5\ m$

Hence, the smallest distance between the speakers for which the interference of the sound waves is maximum constructive is 0.5 m.

4 0

4 years ago

Read 2 more answers