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hammer [34]
3 years ago
14

Calculate the thermal energy in a cubic meter of air at room temperature and one atmosphere. Is it possible to extract this ener

gy to charge your mobile phone? Explain.
Physics
1 answer:
Ksivusya [100]3 years ago
7 0

Answer:

312 kJ

Explanation:

The thermal energy contained in a cubic meter of air at room temperature (20 C) and one atmosphere (101 kPa) would be.

H = Cv * T + p * V

Being

Cv: specific heat of air at constant volme (0.72 kJ/(kg*K))

T: temperature in absolute scale (20C is 293 K)

Then:

H = 0.72 * 293 + 101 * 1 = 312 kJ

The only way to extract thermal energy from a body and turn it into useful work (such as charging a phone) is to exchange heat with it and a another colder body. So, with just the air at room temperature it is impossible to extract its heat energy.

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Write down the relation between energy and power​
gizmo_the_mogwai [7]

Answer:

Energy is what makes change happen and can be transferred form one object to another. Energy can also be transformed from one form to another. Power is the rate at which energy is transferred. It is not energy but is often confused with energy.

Explanation:

6 0
3 years ago
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. A water balloon is thrown horizontally at a speed of 2.00 m/s from the roof of a building that is 6.00m above the ground. At t
dedylja [7]

Answer:

Explanation:

Height of building

H = 6m

Horizontal speed of first balloon

U1x = 2m/s

Second ballot is thrown straight downward at a speed of

U2y = 2m/s

Time each gallon hits the ground

Balloon 1.

Using equation of free fall

H = Uoy•t + ½gt²

Uox = 0 since the body does not have vertical component of velocity

6 = ½ × 9.8t²

6 = 4.9t²

t² = 6 / 4.9

t² = 1.224

t = √1.224

t = 1.11 seconds

For second balloon

H = Uoy•t + ½gt²

6 = 2t + ½ × 9.8t²

6 = 2t + 4.9t²

4.9t² + 2t —6 = 0

Using formula method to solve the quadratic equation

Check attachment

From the solution we see that,

t = 0.9211 and t = -1.329

We will discard the negative value of time since time can't be negative here

So the second balloon get to the ground after t ≈ 0.92 seconds

Conclusion

The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.

4 0
2 years ago
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. Calculate the kinetic energy of a 100.0-kg meteor approaching the Earth at a speed of 10.0 km/s. Remember that 1 km = 1000 m.
anastassius [24]
Ke = (1/2)mv²

m = 100kg, v = 10 km/s = 10*1000 = 10000m/s

Ke = (1/2)*100*10000 

Ke = 500000 Joules
7 0
3 years ago
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Calculate the heat flux (in W/m^2) through a sheet of a metal 14 mm thick if the temperatures at the two faces are 350 and 140°C
ExtremeBDS [4]

Answer:

Explanation:

The rate of conductive heat transfer in watts is:

q = (k/s) A ΔT

where k is the heat conductivity, s is the thickness, A is the area, and ΔT is the temperature difference.

a)

Given k = 52.4 W/m/K, s = 0.014 m, and ΔT = 350-140 = 210 K, we can find q/A:

q/A = (52.4 / 0.014) (210)

q/A = 786,000 W/m²

b)

Given that A = 0.42 m², we can find q:

q = (0.42 m²) (786,000 W/m²)

q = 330,120 W

A watt is a Joule per second.  Convert to Joules per hour:

q = 330,120 J/s * 3600 s/hr

q = 1.19×10⁹ J/hr

c)

If we change k to 1.8 W/m/K:

q = (k/s) A ΔT

q = (1.8 / 0.014) (0.42) (210)

q = 11,340 J/s

q = 4.08×10⁷ J/hr

d)

If k is 52.4 W/m/K and s is 0.024 m:

q = (k/s) A ΔT

q = (52.4 / 0.024) (0.42) (210)

q = 192,570 J/s

q = 6.93×10⁸ J/hr

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3 years ago
Explain why offspring may or may not resemble either parent
katen-ka-za [31]
The offspring can have some features for the parents relatives and can look nothing like the parents. They can look exactly alike to more of one parent then the other or have features from both parents as well
Hope this helps :3
6 0
3 years ago
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