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Vilka [71]
4 years ago
14

which statement tells you where the metalloids are located in the periodic table A.metalloids are the elements to the left of th

e zigzag line B.metalloids are the elements to the right of the zig-zag line C.metalloids are the elements that do not border the zigzag line D. metalloids are the elements except aluminum that border the zigzag line
Physics
1 answer:
IceJOKER [234]4 years ago
5 0
Were is the table at?

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Determine the value of n so that the vectors A and B are perpendicular: Ā = î + 5j + nk and B = 2î - j + k
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If \vec A and \vec B are perpendicular, then their dot product is zero. This means

\vec A \cdot \vec B = (\vec\imath + 5\,\vec\jmath + n\,\vec k) \cdot (2\,\vec\imath - \vec\jmath + \vec k) = 2 - 5 + n = 0

Solving for n is trivial; it follows that n = 3.

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2 years ago
Two pieces of clay are moving directly toward each other. When they collide, they stick together and move as one piece. One piec
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Answer:

The fraction of the total initial kinetic energy is lost during the collision is \dfrac{11}{17}\ J

Explanation:

Given that,

Mass of one piece = 300 g

Speed of one piece = 1 m/s

Mass of other piece = 600 g

Speed of other piece = 0.75 m/s

We need to calculate the final velocity

Using conservation of energy

m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v

Put the value intro the formula

300\times10^{-3}\times1+600\times10^{-3}\times(0.75)=(300\times10^{-3}+600\times10^{-3})v

v=\dfrac{00\times10^{-3}\times1+600\times10^{-3}\times(-0.75)}{(300\times10^{-3}+600\times10^{-3})}

v=-0.5\ m/s

We need to calculate the total initial kinetic energy

Using formula of kinetic energy

K.E_{i}=\dfrac{1}{2}m_{1}v_{1}^2+\dfrac{1}{2}m_{2}v_{2}^2

Put the value into the formula

K.E_{i}=\dfrac{1}{2}\times300\times10^{-3}\times1^2+\dfrac{1}{2}\times600\times10^{-3}\times(0.75)^2

K.E_{i}=0.31875\ J

We need to calculate the total final kinetic energy

Using formula of kinetic energy

K.E_{f}=\dfrac{1}{2}(m_{1}+m_{2})v^2

Put the value into the formula

K.E_{f}=\dfrac{1}{2}\times(300\times10^{-3}+600\times10^{-3})\times(-0.5)^2

K.E_{f}=0.1125\ J

We need to calculate the energy lost during the collision

Using formula of energy lost

energy\ lost=\dfrac{0.31875-0.1125}{0.31875}

energy\ lost=\dfrac{11}{17}\ J

Hence, The fraction of the total initial kinetic energy is lost during the collision is \dfrac{11}{17}\ J

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4 years ago
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