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Vilka [71]
4 years ago
14

which statement tells you where the metalloids are located in the periodic table A.metalloids are the elements to the left of th

e zigzag line B.metalloids are the elements to the right of the zig-zag line C.metalloids are the elements that do not border the zigzag line D. metalloids are the elements except aluminum that border the zigzag line
Physics
1 answer:
IceJOKER [234]4 years ago
5 0
Were is the table at?

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Three metal fishing weights, each with a mass of 1.00x102 g and at a temperature of 100.0°C, are placed in 1.00x102 g of water a
worty [1.4K]

Answer:

Approximately 0.253\; {\rm J \cdot g^{-1} \cdot K^{-1}} assuming no heat exchange between the mixture and the surroundings.

Explanation:

Consider an object of specific heat capacity c and mass m. Increasing the temperature of this object by \Delta T would require Q = c\, m \, \Delta T.

Look up the specific heat of water: c(\text{water}) = 4.182\; {\rm J \cdot g^{-1} \cdot K^{-1}}.

It is given that the mass of the water in this mixture is m(\text{water}) = 1.00 \times 10^{2}\; {\rm g}.

Temperature change of the water: \Delta T(\text{water}) = (45 - 35)\; {\rm K} = 10\; {\rm K}.

Thus, the water in this mixture would have absorbed :

\begin{aligned}Q &= c\, m\, \Delta T \\ &= 4.182\; {\rm J \cdot g^{-1}\cdot K^{-1}} \\ &\quad \times 1.00 \times 10^{2}\; {\rm g} \times 10\; {\rm K} \\ &= 4.182 \times 10^{3}\; {\rm J}\end{aligned}.

Thus, the energy that water absorbed was: Q(\text{water}) = 4.182 \times 10^{3}\; {\rm J}.

Assuming that there was no heat exchange between the mixture and its surroundings. The energy that the water in this mixture absorbed, Q(\text{water}), would be the opposite of the energy that the metal in this mixture released.

Thus: Q(\text{metal}) = -Q(\text{water}) = -4.182 \times 10^{3}\; {\rm J} (negative because the metal in this mixture released energy rather than absorbing energy.)

Mass of the metal in this mixture: m(\text{metal}) = 3 \times 1.00 \times 10^{2}\; {\rm g} = 3.00 \times 10^{2}\; {\rm g}.

Temperature change of the metal in this mixture: \Delta T(\text{metal}) = (100 - 45)\; {\rm K} = 55\; {\rm K}.

Rearrange the equation Q = c\, m \, \Delta T to obtain an expression for the specific heat capacity: c = Q / (m\, \Delta T). The (average) specific heat capacity of the metal pieces in this mixture would be:

\begin{aligned}c &= \frac{Q}{m\, \Delta T} \\ &= \frac{-4.182 \times 10^{3}\; {\rm J}}{3.00 \times 10^{2}\; {\rm g} \times (-55\; {\rm K})} \\ &\approx 0.253\; {\rm J \cdot g^{-1} \cdot K^{-1}}\end{aligned}.

6 0
2 years ago
Can a relative velocity of two bodies be greater than the absolute velocity of
steposvetlana [31]

Yes, eg., when 2 bodies move in opposite directions

, the relative velocity of each is greater than the individual velocity of either

8 0
3 years ago
To open a soda can lid, you can apply a force of 50 N to a car key wedged under
AysviL [449]

Answer:

7.8

Explanation:

Here, an effort of 50 N is applied at the car key and overcomes the resistance(or load) of 390 N at the lid.

mechanical advantage

=load/effort

=390 N/50 N

=7.8

8 0
3 years ago
Find the length of each vector below.
Leona [35]

Answer:

a. 3.6 units

b. 1.4 units

c. 3.6 units

d. 6.1 units

Explanation:

The length of a vector is given by the following formula:

Length = √(x² + y²)

where,

x = x-component of vector

y = y-component of vector

a.

Here,

x = 2

y = 3

Therefore,

Length = √(2² + 3²)

Length = √13

<u>Length = 3.6 units</u>

<u />

b.

Here,

x = 1

y = 1

Therefore,

Length = √(1² + 1²)

Length = √2

<u>Length = 1.4 units</u>

<u />

c.

Here,

x = 2

y = -3

Therefore,

Length = √(2² + (-3)²)

Length = √13

<u>Length = 3.6 units</u>

<u />

d.

Here,

x = 1

y = -6

Therefore,

Length = √(1² + (-6)²)

Length = √37

<u>Length = 6.1 units</u>

8 0
3 years ago
which of the following is not used to protect us from the possibility of receiving an electric shock​
Juli2301 [7.4K]

Answer:water

Explanation:

6 0
3 years ago
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