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Scrat [10]
3 years ago
12

A helicopter goes straight up 500m from a landing pad. It then goes north 20m. Then it goes down 452m. a) What is the displaceme

nt of the helicopter?
Express as components of a vector.
x-component_____________________
y-component_____________________

b) What is the displacement of the helicopter? Express as a vector (magnitude and direction).

Answer_____________________
Physics
1 answer:
gavmur [86]3 years ago
3 0

Answer:

a

  x-component             20 \  m

y-component     500 -  452 =  48 \  m

b

 Magnitude d  =  52 \  m

direction is  \theta  = 67.4^o

Explanation:

From the question we are told that

   The first  vertical distance is  y_1   = 500 \  m

    The  first horizontal distance  is  x =  20 \  m

    The  second vertical distance is  y_2  =  452 \  m

Generally the displacement is  

x-component             20 \  m

y-component     500 -  452 =  48 \  m

Generally the helicopters displacement is mathematically evaluated as  

       d  =  \sqrt{ x- component ^2  +  y- component ^2 }

      d  =  \sqrt{ 20t ^2  + 48 ^2 }

      d  =  52 \  m

The  direction is the angle the displacement of the helicopter makes with the horizontal which is mathematically evaluated as

         \theta  = tan ^{-1}[ \frac{48}{20}]

=>       \theta  = tan ^{-1}[ 2.4 ]

=>      \theta  = 67.4^o

   

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