Applying 1st law of thermodynamics:
Q = Delta U + WB
WB is the workdone by the system
<span>WB = 346 J </span>
As,
<span>Delta U = ( m ) ( CV ) ( T2 - T1 ) </span>
<span>CV = ( Delta U ) / ( m ) ( T2 - T1 )
</span>Putting the values in equation:
<span>CV = ( 8485 J ) / ( 80.0 g ) ( 225 C - 25 C ) </span>
<span>CV = 0.5303 J / g - C degree </span>
Now putting in original equation:
<span>Q = Delta U + WB </span>
<span>Q = ( 8485 ) + ( 346 ) = 8831 J
8831J is the specific heat of the gas</span>
Answer: The Answer is A.
Explanation:
The amount of energy is directly proportional to the photon's electromagnetic frequency and thus, equivalently, is inversely proportional to the wavelength. The higher the photon's frequency, the higher its energy. Equivalently, the longer the photon's wavelength, the lower its energy.
Hope this Helps!
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