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Rufina [12.5K]
3 years ago
15

**URGENT**** Which group of elements has the highest boiling point? *

Chemistry
2 answers:
iris [78.8K]3 years ago
6 0

Answer:  the elements that have the hightse boiling is trnsition metals

xplanation:

Ray Of Light [21]3 years ago
4 0
I think transmition metals as These properties are due to metallic bonding by delocalized d electrons, leading to cohesion which increases with the number of shared electrons.
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Which atomic model was proposed as a result of J. J. Thomson’s work? the plum pudding model the indivisible atom model an atom t
olga2289 [7]

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A. The plum pudding model.

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4 years ago
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How do you prepare diluted acid from concentrated acid?
lidiya [134]
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4 0
3 years ago
Metallic aluminum reacts with MnO2 at elevated temperatures to form manganese metal and aluminum oxide. A mixture of the two rea
Oksi-84 [34.3K]

Answer:

Explanation:

To find the theoretical yield of the equation. First identify the limiting reactant in a chemical equation.

Step 1: write out the equation and balance it.

Al+ 3mno2=3mn+ 2Alo3.

The limiting reactant is mn02 because it is not found in excess.

Step 2: convert the % to gram . All contain 67.2% mole and mno2 will be 100-67.2= 32.8

All=67.2÷100×290(total gram of the reactants)=194.88g

Mno2=32.8÷100×290g=94.12g.

Step 3:calculate the molar mass of mno2 and that of mn. The atomic mass of mn is 54.9380 and that of oxygen is 16.

Mno2=54.938+ (16)2=86.98g/mol.

Mn=54.938.

Step 4:

From your balanced equation , calculate mn.

94.12g mno2× (1mol mno2÷86.98(molarmass) of mno2×3 mol of mn/4molAl×54.938g of mn÷1mol of mn.

94.12g×1÷86.98g×3÷4×54.938÷1

=44.58g

6 0
3 years ago
The element silver (Ag) has two naturally occurring isotopes: 109Ag and 107Ag with a mass of 106.905 amu. Silver consists of 51.
algol [13]

Answer:

108.76 amu is the mass of 109Ag

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, 109Ag:

% = 51.82 %

Mass = x amu

For second isotope, 107Ag:

% = 100  - x   = 100 - 51.82 % = 48.18 %

Mass = 106.905 amu

Given, Average Mass = 107.868 amu

Thus,  

107.868=\frac{51.82}{100}\times {x}+\frac{48.18}{100}\times {106.905}

Solving for x, we get that:

x = 108.76 amu

<u>108.76 amu is the mass of 109Ag</u>

6 0
3 years ago
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