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My name is Ann [436]
3 years ago
8

The first step in planning effective writing is to consider the _____

Computers and Technology
1 answer:
Amiraneli [1.4K]3 years ago
8 0

Its the purpose, not the audience the other idiot that answered the question is mad wrong

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The arcade machine market crash in the 1980's because:
Blababa [14]

Answer:

C) A quarter was worth less than is used to be.

Explanation:

I got this answer wrong when I chose B.

7 0
3 years ago
What purpose would tracking changes be most useful for?
olya-2409 [2.1K]
So, you can be able to make a prediction and understand the cycle.
6 0
3 years ago
class student_record { public: int age; string name; double gpa; }; Implement a void function that has five formal parameters: a
Setler79 [48]

Answer:

void delete_record(student_record *arr, int &size, int age, string name, double gpa) {

int index = -1;

if (arr != NULL && size > 0) {

for (int i = 0; i < size; ++i) {

if (arr[i].age == age && arr[i].name == name && arr[i].gpa == gpa) {

index = i;

break;

}

}

}

if (index != -1) {

for (int i = index; i < size - 1; ++i) {

arr[i] = arr[i + 1];

}

size--;

}

}

8 0
3 years ago
Assign True to the variable has_dups if the string s1 has any duplicate character (that is if any character appears more than on
podryga [215]

Answer:

#include <iostream>

using namespace std;

int main()

{

   string s;

   cin>>s;    //reading string

   int i,j;

   bool has_dups=false;

   int n= s.length();

   for(i=0;i<n;i++)  //to check for duplicate characters

   {

       for(j=0;j<n;j++)

       {

           if(j!=i && s[i]==s[j])  //to check if it is matched with itself

           {

               has_dups=true;  //if true no need to check others

               break;

           }

       }

   }

   cout<<has_dups;

   return 0;

}

OUTPUT :

California

1

Explanation:

Above program finds if a character repeat itself in the string entered by user.

4 0
3 years ago
Write structured pseudocode to show the following: when you are on time for work you have time to buy coffee
faltersainse [42]

Answer:

If( on_time == True) {

     print("Coffee")

} else {

    print("No Coffee")

}

Explanation:

Step 1 evaluate with a boolean variable if you are on time

If( on_time == True) {

Step 2 if true you have coffee

print("Coffee")

Step 3 if false you have not coffee

print("No Coffee")

3 0
3 years ago
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