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Ad libitum [116K]
3 years ago
5

Thanks for any help provided to me! :3

Mathematics
1 answer:
enyata [817]3 years ago
7 0

Answer:

0.25

Step-by-step explanation:

Average means \frac{total \: number}{number \:  \: of  \: \: individuals}

According to the formula, each student in Mr. Goldwasser's class read

\frac{66}{24}  = 2.75

books on average, and each student in Mr. Welch's class read

\frac{65}{26}  = 2.5

books on average.

Therefore, the answer will be

2.75 - 2.5 = 0.25

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A simple random sample was taken of 44 water bottles from a bottling plant’s warehouse. The dissolvedoxygen content (in mg/L) wa
AleksAgata [21]

Answer:

a)9.14-2.33\frac{2}{\sqrt{44}}=8.44    

9.14+2.33\frac{2}{\sqrt{44}}=9.84    

b) The 98% confidence interval would be given by (8.44;9.84)    

For this case we can conclude that we have 98% of confidence that the true mean for the oxygen content is between 8.44 and 9.84 mg/L

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=9.14 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=2 represent the population standard deviation

n=44 represent the sample size  

Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=18-1=17

Since the Confidence is 0.98 or 98%, the value of \alpha=0.01 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.01,0,1)".And we see that z_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

9.14-2.33\frac{2}{\sqrt{44}}=8.44    

9.14+2.33\frac{2}{\sqrt{44}}=9.84    

Part b

The 98% confidence interval would be given by (8.44;9.84)    

For this case we can conclude that we have 98% of confidence that the true mean for the oxygen content is between 8.44 and 9.84 mg/L

3 0
4 years ago
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im going to say d but im not good at math


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Answer:

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Step-by-step explanation:

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8.8^2 = 77.44

This is a good approximation

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