Question

What's the correct answer for this?

Answer 1

$\bf \qquad \qquad \textit{inverse proportional variation}\\\\ \textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array}\\\\ -------------------------------$

$\bf \textit{\underline{N} is inversely proportional to \underline{A}}\qquad N=\cfrac{k}{A} \\\\\\ \textit{we also know that } \begin{cases} A=3\\ N=16 \end{cases}\implies 16=\cfrac{k}{3}\implies 16\cdot 3=k \\\\\\ 48=k\qquad thus\qquad \boxed{N=\cfrac{48}{A}}\\\\ -------------------------------\\\\ \textit{if \underline{A} is 4, what is \underline{N}?}\qquad N=\cfrac{48}{4}$