Answer:
3.1 ns ; 1.25 ; 3.097
Explanation:
Given :
IF, 3 ns;
ID, 2.5 ns;
EX, 2 ns;
MEM, 3 ns;
WB, 1.5 ns.
Use 0.1 ns for the pipelineregisterdelay
maximum time required for MEM = 3 ns
Pipeline register delay = 0.1 ns.
Clock cycled time of the pipelined machine= maximum time required + delay
3ns+0.1 ns = 3.1 ns
2.) for stall after every 4 instruction :
CPI of new machine :
(1 + (1 /4)) = 1 + 0.25 = 1.25
3.)
The speedup of pipelined machine over the single-cycle machine is given by :
Average time per instruction of single cycle ÷ average time per instruction of pipelined
Clock time of original machine = 12ns
Ideal CP1 = 1
CPI of new machine = 1.25
Clock period = 3.1 ns
(12 * 1) / (1.25 * 3.1) = 12 / 3.875
= 3.097
D. Speed up will equal the number of stages in the machine
Answer:
- Using it
- Selling it
- Giving it to someone.
Explanation:
Copyright law protects the unauthorized access to, reproduction and distribution of copyrighted material. The permission of the copyright holders is needed if any of these are to be done.
If copyrighted material is used without permission such as using software without buying it, that is illegal. If that software is sold or given to someone else, that is also illegal because it can only be distributed or redistributed by the copyright owners or people they have given access to.
Answer:
a. The information is first sent via a Broadband for efficient transmission, and if not successful, only then it is resent via a Baseband that exists as a backup network as packets b. The message is first broken down into small packets before being sent, then they are
Explanation:
When the email was sent as a group email
Answer:
private ip addresses
Explanation:
A private ip address is assigned to each device on a network, allowing devices on the same network to communicate with each other without using any public ip addresses.
