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Orlov [11]
2 years ago
14

What is the circumference and the area of this circle​

Mathematics
1 answer:
alexira [117]2 years ago
3 0
<h2>circumference = 50.24cm</h2><h2>area = 200.96cm²</h2>

Step-by-step explanation:

radius (r) = 8cm

circumference = 2π×r

= 2 × 3.14 × 8

= 50.24cm

area = π × r²

= 3.14 × 8 × 8

= 200.96cm²

<h2>MARK ME BRAINLIST</h2>
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₈C₂ = 8!/(2!6!)
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What is the unit price for a piece of cheese if 3.25 pounds costs $19.50?
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$6

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There are 24 muffins in a bakery. If 3/8 of the muffins are blueberry, how many muffins are blueberry?
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What other information do you need in order to prove the triangles congruent using the SAS Congruence Postulate?
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<CBA = <CDA

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Describe the rotation of J
Serga [27]

Answer:

The coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1)

The coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)

Step-by-step explanation:

Square JKLM with vertices

  • J(1, -3)
  • K(5, 0)
  • L(8, -4)
  • M(4, -7)

We have to determine the answer for the image J' of the point (1, -3) when we rotate the point by 90° counterclockwise, we need to switch x and y, make y negative.

In other words, the rule to rotate a point by 90° counterclockwise.

P(x, y) → P'(-y, x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(3, 1)

Therefore, the coordinates of J' when rotating by 90° counterclockwise will be:  J'(3, 1).

When the point is rotated by 90° clockwise, we need to switch x and y, make x negative.

In other words, the rule to rotate a point by 90° clockwise.

P(x, y) → P'(y, -x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(-3, -1)

Therefore, the coordinates of J' when rotating by 90° clockwise will be:  J'(-3, -1)

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2 years ago
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