Answer:
d = 1.65 m
Explanation:
Given that,
The speed of a ball, v = 3 m/s
A ball rolls a level table that is 1.5 m above the floor.
We can find how long the ball is in free fall. We can use the second equation of kinematics as follows :

u is the initial speed in the vertical direction
So,

Now, using the formula of velocity.

So, the landing spot is at 1.65 m from the table.
To solve the problem we first need to define the nomenclature by which there is an X amount of water in our body. Let's call this a variable m, corresponding to the total mass in us and whose units are Kilograms.

We understand that one millionth of this mass, a small fraction of it, is the equivalent of that of a Water Molecule.
Assuming this to have the same body of water in our body that amount should be approximately

Density of water molecule



Answer;
- June 21
At 45 degrees latitude, the angle of the noon sun is lowest and the length of daylight is shortest on June 21.
Explanation;
-On June 21 you will note that the Northern Hemisphere is pitched toward the Sun. This means that the Sun's vertical ray is striking the Earth at the Tropic of Cancer (23.5 degrees N).
-Days tend to get longer in the northern hemisphere from December 21 to June 21, and then grow shorter from June 21 to December 21. The June solstice is the summer solstice in the Northern Hemisphere and the winter solstice in the Southern Hemisphere. The date varies between June 20 and June 22, depending on the year, and the local time zone.
What happens in the prism stays in the prism. When the light emerges, it has the same frequency and wavelength as when it entered. The prism permanently alters nothing but the angle.
<span>Reference https://www.physicsforums.com/threads/how-does-a-prism-affect-wavelength.489768/ by caseytrimble
Sorry this probably doesn't help
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The zero net electric field point is at a point that is 0.98 m away from 4.7C charge.If a 14C charge is placed at this point then, force acted on the charge placed at this point is equal to zero.
Explanation:
Let at A both net electric field is zero then
At A ,E1=E2
E1=k*Iq1I / (d+x)^2
E2=k*Iq2I /x^2
Equating both