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Ivan
3 years ago
13

Lindsay draws a right triangle and adds the measures of the right angle and one acute angle. Which is a possible sum of the two

angles?
Mathematics
2 answers:
Anon25 [30]3 years ago
6 0
Anything between 91 degrees and 179 degrees. You can pick any between these two.
Viktor [21]3 years ago
4 0

Answer:

90< \gamma< 180

Step-by-step explanation:

An acute angle is an angle that measures more than 0º and less than 90º. And a right angle is an angle that measures exactly 90º. Thus:

Let:

\alpha = Right\hspace{3}angle=90^{\circ}\\\beta= Acute\hspace{3}angle\hspace{10}0^{\circ}

So, in this sense, the sum of the two angles can´t be equal or greater than 180º, since \beta , also it has to be at least greater than 90º since \beta>0^{\circ}

Therefore the sum of the two angles is:

90^{\circ}< \gamma< 180^{\circ}

In another words, the sum is greater than 90º and less than 180º

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In ΔKLM, the measure of ∠M=90°, LK = 97, ML = 65, and KM = 72. What is the value of the sine of ∠L to the nearest hundredth?
Sphinxa [80]

Answer:

0.74

Step-by-step explanation:

72/97 is 0.74 rounded to the nearest hundredths.

6 0
3 years ago
Plzz helpp mee in this question!!!​
VashaNatasha [74]

Answer:

Please see attached picture for full solution.

4 0
3 years ago
To one-one functions g and h are defined as follows.
Andreyy89

Answer:

  • 9
  • (x-8)/3
  • -1

Step-by-step explanation:

The inverse function for a set of ordered pairs can be found by swapping the x- and y-coordinates in each pair.

  g^{-1}(-1)=9\qquad\text{from the $g(x)$ ordered pair $(9, -1)$}

__

The inverse of a function expressed algebraically can be found by swapping the x- and y-variables and solving for y.

  h^{-1}(x)\qquad\text{is found from }x=h(y)\\\\x=3y+8\\x-8=3y\\\\y=\dfrac{x-8}{3}\\\\\boxed{h^{-1}(x)=\dfrac{x-8}{3}}

A function of its own inverse returns the original value:

  \boxed{\left(h\circ h^{-1}\right)(-1)=-1}

6 0
3 years ago
Suppose in the population, the Anger-Out score for men is two points higher than it is for women. The population variances for m
tatuchka [14]

Answer:

a)= 2

b) 6.324

c) P= 0.1217

Step-by-step explanation:

a) The mean of the sampling distribution of X`1- X`2 denoted by ux`-x` = u1-u2 is equal to the difference between population means i.e = 2 ( given in the question)

b) The standard deviation of the sampling distribution of X`1- X`2 ( standard error of X`1- X`2) denoted by σ_X`1- X`2 is given by

σ_X`1- X`2 = √σ²/n1 +σ²/n2

Var ( X`1- X`2) = Var X`1 + Var X`2 =  σ²/n1 +σ²/n2

so

σ_X`1- X`2 =√20 +20 = 6.324

if the populations are normal the sampling distribution X`1- X`2 , regardless of sample sizes , will be normal with mean u1-u2 and variance σ²/n1 +σ²/n2.

Where as Z is normally distributed with mean zero and unit variance.

If we take X`1- X`2= 0 and u1-u2= 2  and standard deviation of the sampling distribution = 6.324 then

Z= 0-2/ 6.342= -0.31625

P(-0.31625<z<0)= 0.1217

The probability would be 0.1217

8 0
2 years ago
Convert 30 m/s to miles per hour.<br> Use 1 mile per hour = 1.61 km/h
ss7ja [257]

Answer:

1 = 1.61

30 = x

1.61 x 30 =

48.3

7 0
3 years ago
Read 2 more answers
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