Answer: here you go,have a great day
Step-by-step explanation:
Answer:
2.4
Step-by-step explanation:
Answer:
Step-by-step explanation:
Interesting problem.
At 6<x<8,
f(x) = x-7
at 5<x<8
g(x) = (15-x)/2
=>
y(x)
= f(x)*g(x)
= (x-7)(15-x)/2
= (x^2+22x-105)/2
differentiate y(x) with respect to x,
y'(x) = -x+11
at x = 7,
y'(7) = -(7) + 11 = 4


Evaluating c = 4 in equation .





(x + 1.5)^2 - 1.25
This is because you have to take half of the x value and place it in the parenthesis. Then you have to square that number and subtract to get the original c value.