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nikklg [1K]
3 years ago
9

How can the force of friction between two surfaces be reduced?

Physics
2 answers:
Stells [14]3 years ago
5 0
B if you make it rougher they won’t be able to have frictions
vodomira [7]3 years ago
4 0
C because it will reduce the friction and help the object work together
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An object travels a given distance at a speed of 5 m/s. If the object travels the same distance at a higher speed, how will the
OverLord2011 [107]

a. it will take less time

4 0
4 years ago
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According to string theory, six space-time dimensions cannot be measured except as quantum numbers of internal particle properti
m_a_m_a [10]

Answer:

10^{-35}\ meters

Explanation:

The string theory is a theoretical concept, the very small particles of particle physics are rep[laced by strings. This theory also applies to black hole physics, nuclear physics, cosmology etc.

According to string theory, six space-time dimensions cannot be measured except as quantum numbers of internal particle properties because they are curled up in size of the order of 10^{-35}\ m.

The length of the scale is assumed to be on the order of 10^{-35}\ m. Hence, the correct option is (a).

5 0
3 years ago
A car of mass 1200Kilograms moving at 15 m/s the driver applies the brakes for 0.08 seconds and the castles down to 10 meter per
denpristay [2]
  • Initial velocity=u=15m/s
  • Final velocity=v=10m/s
  • Time=0.08s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{10-15}{0.08}

\\ \sf\longmapsto Acceleration=\dfrac{-5}{0.08}

\\ \sf\longmapsto Acceleration=-62.5m/s^2

5 0
3 years ago
The acceleration due to gravity on or near the surface of Earth is 32 ft./s/s. Neglecting friction, from what height must a ston
svetoff [14.1K]

Given :

The acceleration due to gravity on or near the surface of Earth is 32 ft/s/s

To Find :

From what height must a stone be dropped on Earth to strike the ground with a velocity of 136 ft/s.

Solution :

Initial velocity of stone, u = 0 ft/s.

Now, by equation of motion :

2as =  v^2 -u^2 \\\\2\times 32 \times s = 136^2 -0^2\\\\s = \dfrac{136^2}{2\times 32}\ ft\\\\s = 289 \ ft

Therefore, height from which stone is thrown is 289 ft.

3 0
3 years ago
You apply a 150 N push on a frictionless sled over a period of 2 seconds. Show that the sled’s momentum changes by 300 kg·m/s.
Savatey [412]

Explanation:

Given parameters:

Force applied = 150N

Time  = 2s

Unknown:

Momentum change = ?

Solution:

The momentum change of a body is the difference between its initial and final momentum.

Momentum is the same as the impulse exerted on a body which is the product of force  and time

   Momentum = mass x velocity = force x time

The body initially at rest has a momentum of 0, as the momentum changes;

      Momentum change = Final momentum - initial momentum

                                         = f x t - (0)

                                         = (150 x 2) - 0

     Momentum change = 300kgm/s

Since the body is a frictionless surface, the net force is the same as the applied force.

learn more

Momentum brainly.com/question/9484203

#learnwithBrainly

8 0
3 years ago
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