Ask question

Ask question

All categories

2 years ago

12

A car of mass 1200Kilograms moving at 15 m/s the driver applies the brakes for 0.08 seconds and the castles down to 10 meter per

second calculate the acceleration of the car

1 answer:

denpristay [2]2 years ago

5 0

Initial velocity=u=15m/s
Final velocity=v=10m/s
Time=0.08s

$\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}$

$\\ \sf\longmapsto Acceleration=\dfrac{10-15}{0.08}$

$\\ \sf\longmapsto Acceleration=\dfrac{-5}{0.08}$

$\\ \sf\longmapsto Acceleration=-62.5m/s^2$

You might be interested in

If the ratio between the frequency of a man's voice and that of a girl's voice is 3/4, what

shepuryov [24]

Answer:

it is 34

34 is th answer

Explanation:

8 0

2 years ago

What is salinity ? ..

AveGali [126]

Answer:

<h3>Salinity is the saltiness or amount of salt dissolved in a body of water, called saline water. It is usually measured in g/L or g/kg. </h3>

7 0

2 years ago

Read 2 more answers

What force cause the rod to become charged

gtnhenbr [62]

Answer:

electricity

If a rod is charged it is because of the electrical force acting on it

6 0

2 years ago

Which statement is true about the Big Bang Theory?

zmey [24]

I think it’s A.) it explains why the universe is made up of matter

4 0

2 years ago

Suppose a gliding 2-kg cart bumps into, and sticks to, a stationary 5-kg cart. If the speed of the gliding cart before the colli

Thepotemich [5.8K]

Answer:

Therefore,

Final velocity of the coupled carts after the collision is

$v_{f}=4\ m/s$

Explanation:

Given:

Mass of Glidding Cart = m₁ = 2 kg

Mass of Stationary Cart = m₂ = 5 kg

Initial velocity of Glidding Cart = u₁ = 14 m/s

Initial velocity of Stationary Cart = u₂ = 0 m/s

To Find:

Final velocity of the coupled carts after the collision = $v_{f}=?$

Solution:

Law of Conservation of Momentum:

For a collision occurring between two objects in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

It is denoted by "p" and given by

Momentum = p = mass × velocity

Hence by law of Conservation of Momentum we hame

Momentum before collision = Momentum after collision

Here after collision both are stuck together so both will have same final velocity,

$m_{1}\times u_{1}+m_{2}\times u_{2}=(m_{1}+m_{2})\times v_{f}$

Substituting the values we get

$2\times 14 + 5\times 0 =(2+5)\times v_{f}$

$v_{f}=\dfrac{28}{7}=4\ m/s$

Therefore,

Final velocity of the coupled carts after the collision is

$v_{f}=4\ m/s$

8 0

2 years ago