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shusha [124]
2 years ago
12

A car of mass 1200Kilograms moving at 15 m/s the driver applies the brakes for 0.08 seconds and the castles down to 10 meter per

second calculate the acceleration of the car
Physics
1 answer:
denpristay [2]2 years ago
5 0
  • Initial velocity=u=15m/s
  • Final velocity=v=10m/s
  • Time=0.08s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{10-15}{0.08}

\\ \sf\longmapsto Acceleration=\dfrac{-5}{0.08}

\\ \sf\longmapsto Acceleration=-62.5m/s^2

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Answer:

Rowan's feet appears at a distance of 0.451 m under water

Solution:

As per the question:

Actual depth in water, d = 0.60 m

Normal distance of her feet from her eyes, D = 1.60 m

Now,

We know that refractive index of water, n_{w} = 1.33

Thus

To calculate the apparent height of her feet:

n_{w} = \frac{d}{Apparent\ Height, H_{apparent}}

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6 0
3 years ago
The orbital radius of the Earth (from Earth to Sun) is 1.496 x 10^11 m.
mrs_skeptik [129]

Explanation:

The orbital radius of the Earth is r_1=1.496\times 10^{11}\ m

The orbital radius of the Mercury is r_2=5.79 \times 10^{10}\ m

The orbital radius of the Pluto is r_3=5.91 \times 10^{12}\ m

We need to find the time required for light to travel from the Sun to each of the  three planets.

(a) For Sun -Earth,

Kepler's third law :

T_1^2=\dfrac{4\pi ^2}{GM}r_1^3

M is mass of sun, M=1.989\times 10^{30}\ kg

So,

T_1^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 1.496\times 10^{11}\\\\T_1=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times1.496\times10^{11}}\\\\T_1=2\times 10^{-4}\ s

(b) For Sun -Mercury,

T_2^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 5.79 \times 10^{10}\ m\\\\T_2=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times 5.79 \times 10^{10}}\ m\\\\T_2=1.31\times 10^{-4}\ s

(c) For Sun-Pluto,

T_3^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 5.91 \times 10^{12}\\\\T_3=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times 5.91 \times 10^{12}}\\\\T_3=1.32\times 10^{-3}\ s

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3 years ago
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