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2 years ago

Find the term that must be added to the equation x^2+6x=1 to make it into a perfect square

Mathematics

1 answer:

baherus [9]2 years ago

8 0

Answer:

Step-by-step explanation:

Half of b, and then square that is how to complete the square. Therefore, half of b is 3 and square of 3 is 9.

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Graph the image of this figure after a dilation with a scale factor of 1/3 centered at the origin.

posledela

Answer:

see attached diagram

Step-by-step explanation:

A dilation with a scale factor of $\dfrac{1}{3}$ centered at the origin has a rule:

$(x,y)\mapsto\left(\dfrac{x}{3},\dfrac{y}{3}\right).$

Then the image of the triangle ABC is triangle DEF(see attached diagram) with coordinates

$D\left(\dfrac{-3}{3},\dfrac{3}{3}\right)\Rightarrow D(-1,1);$
$E\left(\dfrac{3}{3},\dfrac{9}{3}\right)\Rightarrow E(1,3);$
$F\left(\dfrac{6}{3},\dfrac{6}{3}\right)\Rightarrow F(2,2).$

3 0

3 years ago

What is the discontinuity and zero of the function f(x) = the quantity of 3 x squared plus x minus 4, all over x minus 1? A. Dis

Firlakuza [10]

Answer:

The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)

Step-by-step explanation:

$\text{The function is given to be : }f(x)=\frac{3x^2+x-4}{x-1}\\\\\implies f(x)=\frac{(3x+4)(x-1)}{(x-1)}$

To find the point of discontinuity :

Put the denominator equal to 0

⇒ x - 1 = 0

⇒ x = 1

Also, if the factor (x - 1) gets cancel, then it becomes a hole rather than a asymptote , ⇒ y = 3x + 4 at x = 1

⇒ y = 7

So, Point of discontinuity : (1, 7)

And the zero is : after cancelling the factor (x - 1) put the remaining factor = 0

⇒ 3x + 4 = 0

⇒ 3x = -4

⇒ x = negative four thirds ( zero of the function)

Therefore, The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)

4 0

3 years ago

Read 2 more answers

Pls answer bb I give extra pp-oints (::

DENIUS [597]

Answer:let me know please

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A rocking horse has a weight limit of 60pounds. What percentage of the weight limit is 33 pounds? What percentage of the weight

bixtya [17]

Answer:

The percentage is 55% when weight limit is 33 pounds.

The percentage is 190% when weight limit is 114 pounds.

The 95% of the limit weighs 57 pounds.

Step-by-step explanation:

Given:

Weight limit of rocking horse = 60 pounds.

We need to find:

a) What percentage of the weight limit is 33 pounds.

b)What percentage of the weight limit is 114 pounds.

c) What weight is 95% of the limit.

Now Solving for a we get;

Weight limit = 33 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{33}{60}\times100 = 55\%$

Hence The percentage is 55% when weight limit is 33 pounds.

Now Solving for b we get;

Weight limit = 114 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{114}{60}\times100 = 190\%$

Hence The percentage is 190% when weight limit is 114 pounds.

Now Solving for c we get;

Percentage Weight = 95%

Now Amount of weight limit can be calculated by multiplying Percentage weight limit with total weight limit and then Dividing by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{95}{100}\times60 = 57 \pounds$

Hence The 95% of the limit weighs 57 pounds.

4 0

4 years ago

Which expression is equivalent to (2^3) ^5? оооо

gregori [183]

Step-by-step explanation:

$\text{Use}\ (a^n)^m=a^{nm}\\\\(2^3)^5=2^{3\cdot5}=2^{15}$

6 0

3 years ago

Read 2 more answers