Question

An aqueous solution contains 0.100 m naoh at 25.0 °c. the ph of the solution is ________.

Answer 1

Recall; pH + pOH = 14
In this case [OH-] =0.100 m
therefore;
pOH = -LOG[OH-]
         = - Log (0.100)
         = 1.00
 Therefore; the pOH is 1.00
And since, pH +pOH = 14
Then pH = 14-pOH
                = 14 -1
                 = 13
Thus the pH is 13.00