A dog has a mass of 19 kg. What is the mass of the dog in grams,expressed in scientific notation
2 answers:
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Answer:
<em>a)</em> <em>1.392 x 10^6 g/cm^3</em>
<em>b) 8.69 x 10^7 lb/ft^3</em>
<em></em>
Explanation:
mass of the star m = 2.0 x 10^36 kg
radius of the star (assumed to be spherical) r = 7.0 x 10^5 km = 7.0 x 10^8 m
The density of substance ρ = mass/volume
The volume of the star = volume of a sphere =
==> V = = 1.437 x 10^27 m^3
density of the star ρ = (2.0 x 10^36)/(1.437 x 10^27) = 1.392 x 10^9 kg/m^3
in g/cm^3 = (1.392 x 10^9)/1000 = <em>1.392 x 10^6 g/cm^3</em>
in lb/ft^3 = (1.392 x 10^9)/16.018 = <em>8.69 x 10^7 lb/ft^3</em>
Answer:
The pressure in the new flask would be if the
here acts like an ideal gas.
Explanation:
Assume that the sample here acts like an ideal gas. By Boyle's Law, the pressure
of the gas should be inversely proportional to its volume
.
For example, let the initial volume and pressure of the sample be and
. The new volume
and pressure
of this sample shall satisfy the equation:
.
In this question,
- The initial volume of the gas is
.
- The initial pressure of the gas is
.
- The new volume of the gas is
.
The goal is to find the new pressure of this gas, .
Assume that this sample is indeed an ideal gas. Then the equation should still hold. Rearrange the equation to separate the unknown,
. Note: make sure that the units for
and
are the same before evaluating. That way, the unit of
.