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denis23 [38]
2 years ago
14

!!!!!PLEASE HELP!!!!!

Chemistry
1 answer:
ollegr [7]2 years ago
3 0

Answer:

Difference in the potential energy of the reactants and products

Explanation:

 

The products have a lower potential energy than the reactants, and the sign of ΔH is negative. In an endothermic reaction, energy is absorbed. The products have a higher potential energy than the reactants, and the sign of ΔH is positive.

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3. Did pushing (compression), pulling (tension), or sideways forces (shear) in the rock layers produce the folds and faults?
Neko [114]

Pushing(Compression) Causes the faults and folds


3 0
3 years ago
How many sigma and pi bonds does it contain ch3chchco2h?
ira [324]
Answer:
            But-2-enoic acid has 11 Sigma Bonds and 2 Pi Bonds.

Explanation:
                   The sigma bonds which are formed due to head to head overlap of partally filled orbitals are shown in red color, while Pi bonds which are formed after the formation of sigma bond by overlap of orbitals perpendicular to the sigma bond are shown in blue color.

8 0
3 years ago
An object has a density of 10.00 g/mL. If the object has a volume of<br> 25.00 ml, what is the mass?
SVEN [57.7K]

Answer:

The answer is

<h2>250 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of object = 25 mL

Density = 10 g/mL

The mass of the object is

mass = 25 × 10

We have the final answer as

<h3>250 g</h3>

Hope this helps you

6 0
3 years ago
If 250.0 g of water at 30.0 °C cool to 5.0 °C, how many kilojoules of energy did the water lose?
Y_Kistochka [10]

Answer:

-26.125 kj

Explanation:

Given data:

Mass of water = 250.0 g

Initial temperature = 30.0°C

Final temperature = 5.0°C

Amount of energy lost = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 5.0°C - 30.0°C

ΔT = -25°C

Specific heat of water is 4.18 j/g.°C

Now we will put the values in formula.

Q = m.c. ΔT

Q = 250.0 g × 4.18 j/g.°C × -25°C

Q = -26125 j

J to kJ

-26125 j ×1 kj /1000 j

-26.125 kj

5 0
3 years ago
When a student adds benedict’s solution to a clear solution, the solution turns orange. the student can conclude that the soluti
4vir4ik [10]
Benedict's solution is used to test simple sugars, such as glucose. It is blue solution, when sugar is present, it turns to orange / brick red. Depends on the concentration of sugar.
5 0
2 years ago
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