The probability that a single radar set will detect an enemy plane is 0.9. if we have five radar sets, what is the probability that exactly four sets will detect the plane?
Solution: The given random experiment follows binomial distribution with 
Let x be the number of radar sets that will detect the plane.
We have to find 
Therefore, the probability that exactly four sets will detect the plane is 0.3281
Answer:
The answer would be 129°
Step-by-step explanation:
We know that <em>AZC </em>is a right angle so you would add the 90° ( which is equal to a right angle) to 39° to get your answer :)
Answer:
A The mean for waiter B is higher than the mean for waiter A.
It’s prime because none of the other answers work.
Find where the equation is undefined ( when the denominator is equal to 0.
Since they say x = 5, replace x in the equation see which ones equal o:
5-5 = 0
So we know the denominator has to be (x-5), this now narrows it down to the first two answers.
To find the horizontal asymptote, we need to look at an equation for a rational function: R(x) = ax^n / bx^m, where n is the degree of the numerator and m is the degree of the denominator.
In the equations given neither the numerator or denominators have an exponent ( neither are raised to a power)
so the degrees would be equal.
Since they are equal the horizontal asymptote is the y-intercept, which is given as -2.
This makes the first choice the correct answer.
