X^2+25 A.(x+5)(x+5) B.(x+5)(x-5) C.(x-5)(x/5) D.prime

Solutes in the bloodstream enter cells through osmosis, which is the diffusion of fluid through a semipermeable membrane. Let C

kow [346]

Answer:

since the rate at which concentration inside the cell is proportional to the difference in the concentration of the solute in the blood stream and the concentration within the cell, then the rate of change of concentration within the cell is equals to K(L-C).

Thus, the required differential equation is Δc/Δt = K( L - C ).

Step-by-step explanation:

4 0

2 years ago

What is does a equal

Blababa [14]

Answer:

a = 13

Step-by-step explanation:

We should know that: The sum of the interior angles of the triangle = 180°

Given the measure of the angles: (6a - 2) , (5a - 13) and (5a - 13)

So,

(6a - 2) + (5a - 13) + (5a - 13) = 180°

16 a - 28= 180 ⇒ Add 28 to both sides

16 a = 180 + 28 = 208 ⇒ Divide both sides by 16

a = 208/16 = 13

5 0

3 years ago

Solve for x. 3x+7 = -x-1

alekssr [168]

Answer: x = -2

Step-by-step explanation: 3x+7 = -x-1; add 1 to both sides: 3x+8=-x; subtract 3x from both sides: 8 = -4x; divide by -4 on both sides: -2 = x

4 0

2 years ago

Plz help me!!!

Nadya [2.5K]

To solve this we are going to use the exponential function: $f(t)=a(1(+/-)b)^t$
where
$f(t)$ is the final amount after $t$ years
$a$ is the initial amount
$b$ is the decay or grow rate rate in decimal form
$t$ is the time in years

Expression A
$f(t)=624(0.95)^{4t}$
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate $b$ , we are going to use the formula: $b=|1-base|$ *100%
$b=|1-0.95|$ *100%
$b=0.05$ *100%
$b=$ 5%
We can conclude that expression A decays at a rate of 5% every three months.

Now, to find the initial value of the function, we are going to evaluate the function at $t=0$
$f(t)=624(0.95)^{4t}$
$f(0)=624(0.95)^{0t}$
$f(0)=624(0.95)^{0}$
$f(0)=624(1)$
$f(0)=624$
We can conclude that the initial value of expression A is 624.

Expression B
$f(t)=725(1.12)^{3t}$
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
$b=|1-base|$ *100%
$b=|1-1.12|$ *100
$b=|-0.12|$ *100%
$b=0.12$ *100%
$b=$ 12%
We can conclude that expression B grows at a rate of 12% every 4 months.

Just like before, to find the initial value of the expression, we are going to evaluate it at $t=0$
$f(t)=725(1.12)^{3t}$
$f(0)=725(1.12)^{0t}$
$f(0)=725(1.12)^{0}$
$f(0)=725(1)$
$f(0)=725$
The initial value of expression B is 725.

We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months.

- Expression A has an initial value of 624, while expression B has an initial value of 725.

8 0

2 years ago

How do I find my answer to 188x 31

rodikova [14]

Answer:5,828

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers