Tabitha Tidbits costs $7 per bag, and Figaro Flakes is $5.50 per bag.
You need to set up a system of equations. Use "x" for Tabitha Tidbits and "y" for Figaro Flakes, and let the total cost of each trip equal c. Using the equation ax+by=c, substitute the cost of each trip in for c, and the number of bags for each food for a and b respectively. The two equations will be:
3x+4y=43
3x+6y=54
Isolate x in the first equation and you will get:
x=(43-4y)/3
Substitute the above equation for x into the other equation:
3*((43-4y)/3)+6y=54
Isolate y in this equation, and you will get 11/2, which is 5.5
So the cost of one bag of Figaro Flakes is $5.50
Now substitute this into the equation where you isolated x:
(43-4(5.5))/3
You will get x=7, so a bag of Tabitha Tidbits is $7
Answer:
166.27 m2
Step-by-step explanation:
area of hexagon =
*
where a = length of 1 side
this hexagon is made of 6 equivalent triangle
consider ABC triangle
let AC length be x
<em>AB = 2 * AC = 2x = a</em>

Hence a = 8
<u>hence area of hexagon = </u>
<u>*</u>
<u> = </u>
<u> * </u>
<u> = 166.27 m2</u>
Answer:
i believe its 1,000
Step-by-step explanation:
HOPE THIS HELPED PLS GIVE ME BRAINILEST
Given:
trap door = 130 square feet.
1st item: 6ft 5in wide & 8ft 9in long
⇒ (6ft * 12 in) + 5 in & (8ft *12 in) + 9 in
⇒ 77inches by 105 inches
⇒ 8,085 square inches
2nd item: 13ft 4in wide & 7ft 8in long
⇒ (13ft * 12in)+ 4 in & (7ft *12in) + 8 in
⇒ 160 inches by 92 inches
⇒ 14,720 square inches
3rd item: 5ft 6in wide & 12ft 4in long
⇒ (5 ft * 12in) + 6 in & (12ft * 12in) + 4in
⇒ 66 inches by 148 inches
⇒ 9,768 square inches
130 square feet convert to square inches.
130 sq. ft * 144 sq.in/sq.ft = 18,720 sq. in
18,720 sq. in / 160 inches = 117 inches
Length = 160 inches ; Width = 117 inches
Perimeter = 2(160 + 117)
P = 2(277)
P = 554 inches
If log2 (x-3) =1
It means that:
2^1 = x-3
2=x-3 |+3 to both sides
2+3=x
x=5