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3 years ago

_____ is the ability to do work. A. Force B. Power C. Joules D. Energy

Physics

2 answers:

MaRussiya [10]3 years ago

4 0

The answer is d for your question

SOVA2 [1]3 years ago

4 0

The answer is D-energy

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g A ray of light is incident on a flat reflecting surface and is reflected. If the incident ray makes an angle of 28.7° with the

Alex_Xolod [135]

Answer:

$\theta_2 = 15.8$ degree

Explanation:

given data:

$\theta_1 = 28.7 degree$

accoding to the snell's law

$n_1*sin\theta_1=n_2*sin\theta_2$

where n1 is refracting index of air = 1

n2 is refracting index of glass = 1.55

putting all value to get angle mad by incident ray with normal

$\theta_2 = \frac{1*sin28.7^{o}}{1.55}$

$\theta_2 = 15.8$ degree

3 0

3 years ago

In fatal crashes, more than __________% of passenger car occupants who were totally ejected from the vehicle were killed.

Ierofanga [76]

Answer:

it would be 83% in a fatal crash.

8 0

3 years ago

A spring loaded toy shoots straight upward with a velocity of 4.5 m/s. Determine the maximum height it reaches. Determine the ti

Angelina_Jolie [31]

Recall that

${v_y}^2-{v_{0y}}^2=2a_y(y-y_0)$

At its maximum height $y_{\mathrm{max}}$ , the toy will have 0 vertical velocity, so that

$-\left(4.5\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)y_{\mathrm{max}}$

$\implies y_{\mathrm{max}}=1.0\,\mathrm m$

For the toy to reach this maximum height, it takes time $t$ such that

$\dfrac{0+v_0}2t=y_{\mathrm{max}}\implies t=0.46\,\mathrm s$

which means it takes twice this time, i.e. $t=0.92\,\mathrm s$ , for the toy to reach its original position.

The velocity of the toy when it falls 1.0 m below its starting point is

${v_y}^2-\left(4.5\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(0-1.0\,\mathrm m)$

$\implies{v_y}^2=39.85\,\dfrac{\mathrm m^2}{\mathrm s^2}$

$\implies v_y=-6.4\,\dfrac{\mathrm m}{\mathrm s}$

where we took the negative square root because we expect the toy to be moving in the downward direction.

6 0

3 years ago

Please help!! An astronaut drops a rock on the surface of an asteroid. The rock is released from rest at a height of 0.79 m abov

enot [183]

Answer:

0.87ms‐²

Explanation:

Explanation is on photo above, it is easier to show steps than explain using words

3 0

3 years ago

If the bar magnet is flipped over and the south pole is brought near the hanging ball, the ball will be?

disa [49]

The ball may attracted to the magnet.

<h3>How can we understand that the hanging ball will be attracted to the magnet or not?</h3>

From the question, we understand that the ball is attracted by the north pole of the bar magnet, then the bar magnet flipped over and the south pole is brought near the hanging ball.
As we know, in this type of experiments of bar magnet most of the times the ball is made out of steel.
Steel is a magnetic material.
Magnetic materials gets attracted to the magnet at both the North and South pole.
This can be compared to how neutral objects also gets attracted to the positively and negatively charged rods through the Polarization force.

So, If the bar magnet is flipped over and the south pole is brought near the hanging ball, The ball will be attracted to the magnet.

Learn more about the bar magnet:

brainly.com/question/27943723

#SPJ4

7 0

2 years ago