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2 years ago

I NEED HELP :) ty.............

Physics

1 answer:

Black_prince [1.1K]2 years ago

7 0

Answer:

The answer to your question is given below

Explanation:

From the question given above, we can see that the wave with a higher frequency has a shorter wavelength while that with a lower frequency has a longer wavelength. This is so because the frequency and wavelength of a wave has inverse relationship. This can further be explained by using the following formula:

Velocity = wavelength x frequency

Divide both side by wavelength

Frequency = Velocity /wavelength

Keeping the velocity constant, we have:

Frequency ∝ 1 / wavelength

From the above illustration, we can see clearly that the frequency and wavelength are in inverse relationship. This implies that the higher the frequency, the shorter the wavelength and the shorter the frequency, the higher the wavelength.

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If it takes 100 N to move a box 5 meters, what is the work done on the box?

jeyben [28]

Answer: D. 500 J

=========================================================

Explanation:

To find the amount of work done, we multiply the force by displacement

work = force*displacement

work = (100 N)*(5 m)

work = (100*5) Nm

work = 500 J

In this case, "Nm" refers to "Newton meters" and not "nanometers"

1 newton meter is equal to 1 joule

7 0

3 years ago

calculate earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the s

IceJOKER [234]

Answer:

Hello your question is incomplete below is the complete question

Calculate Earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the sun, Take the eccentricity of Earth's orbit to be 1/60 and its Semimajor axis to be 93,000,000

answer : V = 1.624* 10^-5 m/s

Explanation:

First we have to calculate the value of a

a = 93 * 10^6 mile/m * 1609.344 m

= 149.668 * 10^8 m

next we will express the distance between the earth and the sun

$r = \frac{a(1-E^2)}{1+Ecos\beta }$ --------- (1)

a = 149.668 * 10^8

E (eccentricity ) = ( 1/60 )^2

$\beta$ = 90°

input the given values into equation 1 above

r = 149.626 * 10^9 m

next calculate the Earths velocity of approach towards the sun using this equation

$v^2 = \frac{4\pi^2 }{r_{c} }$ ------ (2)

Note :

Rc = 149.626 * 10^9 m

equation 2 becomes

( $V^2 = (\frac{4\pi^{2} }{149.626*10^9})$

therefore : V = 1.624* 10^-5 m/s

4 0

4 years ago

1. A rock of granite has a mass of 50 kg. if it’s weight in water

igor_vitrenko [27]

Answer:

The first part of the question is asking about BUOYANT FORCE or UPTHRUST.

Upthrust =TRUE WEIGHT-APPARENT WEIGHT

TRUE WEIGHT=mg

TRUE weight=50kg×10m/s²

=500N

upthrust=500N-380N

FB=120N

volume of the rock=mass/density.

since the granite is completely submerged, the volume of the displaced liquid will be equal to the volume of the body.

upthrust=Vdg

120N=V×1000kg/m³×10m/s²

120N=V×10000kg/m²s²

120/10000=V

v=0.012m³

please mark brainliest, hope it helped

6 0

3 years ago

Mercury has a density of 13.56 g/mL. How many kilograms of mercury would you expect to fit in a cylindrical glass cup with a bot

vovangra [49]

Answer:

263.152kg

Explanation:

The density of a substance is related to its mass and volume as follows;

density = mass / volume

mass = density x volume -------------(i)

The substance in question here is mercury which has;

density = 13.56g/mL = 13.56g/cm³

Since the mercury is going to be put in the cylindrical glass, the volume of the cylindrical glass is going to be equal to the volume of the mercury that will be put.

And we know that the;

volume of a cylinder = πr²h

Where;

π = 3.142

r = bottom radius of the cylinder = 5.75inches

h = height of the cylinder = 0.950ft

For uniformity, let's convert the radius and height of the cylinder to their corresponding values in cm

r = 5.75 inches = 5.75 x 2.54 cm = 14.605cm

h = 0.950 ft = 0.950 x 30.48 cm = 28.956cm

Therefore, the volume of the cylinder;

v = 3.142 x (14.605cm)² x 28.956cm = 19406.5cm³

v = 19406.5cm³ [This is also the volume of the mercury necessary to fit the cylinder]

Now the following value has been found;

volume = 19406.5cm³

Substitute the values of density and volume into equation (i) as follows;

mass = 19406.5cm³ x 13.56g/cm³

mass = 263152.14g

Convert the result to kg by dividing by 1000

mass = 263.152kg

Therefore, 263.152kg kilograms of mercury would fit in the cylindrical glass.

3 0

3 years ago

Question 4 of 10

Alexus [3.1K]

Answer:

22.3 kg•m/s

Explanation:

Apex;)

7 0

3 years ago