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amid [387]
3 years ago
10

The amplitude of oscillation is the maximum distance between the oscillating weight and the equilibrium position. Determine the

frequency of oscillation for several different amplitudes by pulling the weight down different amounts while still keeping the simulation within the top and botom boundaries. How does the frequency depend on the amplitude of oscillation
Physics
2 answers:
Eva8 [605]3 years ago
5 0

Answer:

The frequency does not depend on the amplitude for any (ideal) mechanical or electromagnetic waves.

In electromagnetism we have that the relation is:

Velocity = wavelenght*frequency.

So the amplitude of the wave does not have any effect here.

For a mechanical system like an harmonic oscillator (that can be used to describe almost any oscillating system), we have that the frequency is:  

f = (1/2*pi)*√(k/m)

Where m is the mass and k is the constant of the spring, again, you can see that the frequency only depends on the physical properties of the system, and no in how much you displace it from the equilibrium position.

This happens because as more you displace the mass from the equilibrium position, more will be the force acting on the mass, so while the "path" that the mass has to travel is bigger, the mas moves faster, so the frequency remains unaffected.

joja [24]3 years ago
4 0

Answer:

In no case does the amplitude appear, so we would not have to change the period of the system when we change to the amplitude

Explanation:

In the harmonic movement when the amplitude of oscillation increases, body speed also increases, so the frequency remains constant.

When we solve the different case of harmonic movement

Simple pendulum 2pi f = Ra l / g

Spring mass 2pi f = RA k / m

2pi torsion pendulum f = RA I / k

In no case does the amplitude appear, so we would not have to change the period of the system when we change to the amplitude

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What are the periodic variations in Earth's rotation and orbit around the sun that alter the way solar radiation is distributed
Dahasolnce [82]

Answer:

1. The precession of the equinoxes.

2. Changes in the tilt angle of Earth’s rotational axis relative to the plane of Earth’s orbit around the Sun.

3. Variations in the eccentricity

Explanation:

These variations listed above;  the precession of the equinoxes (refers, changes in the timing of the seasons of summer and winter), this occurs on  a roughly about 26,000-year interval; changes in the tilt angle of Earth’s rotational axis relative to the plane of Earth’s orbit around the Sun, this occurs roughly in a 41,000-year interval; and changes in the eccentricity (that is a departure from a perfect circle) of Earth’s orbit around the Sun, occurring on a roughly 100,000-year timescale. which influences the mean annual solar radiation at the top of Earth’s atmosphere.

5 0
3 years ago
The scale on the horizontal axis is 8 s per division and on the vertical axis 5 m per division. What is the time represented by
Nadya [2.5K]

Answer:

24 s

Explanation:

8 s / tic    *    3 tic = 24 sec from origin

8 0
2 years ago
you are sitting behind the bus driver on a moving bus in relation to a person standing on the sidewalk you are what
grigory [225]

You are sitting behind the bus driver on a moving bus in relation to a person standing on the sidewalk you are what

--------------------------

relative to sidewalk you are moving with the driver

4 0
4 years ago
Given that a lever has a mechanical advantage of 6.0 and is 100% efficient, if the resistance is to be lifted 2.0 inches, then h
Shalnov [3]
The mechanical advantage of a machine is the ratio of the force produced by the machine to the force applied to it. Therefore, we may calculate the applied force using:
Mechanical advantage = force by machine / force applied
6 = 2 / force applied
Force applied = 1/3

Thus, the distance that the effort must move will be 1/3 inch
5 0
4 years ago
Read 2 more answers
Light from a laser (lambda= 406.192 nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen
dsp73

Answer:

The spacing between the slits is    d = 0.00145m                

Explanation:

From the question we are told that

  The wavelength of the light is \lambda = 406.192nm = 406.192*10^{-9} m

   The distance of the slit from the screen is D = 5.937 \ m

    The number of bright fringe is n = 24

     The  length the fringes span is   L = 39.835 mm = \frac{39.835 }{1000} = 0.0398 m

The fringe width (i.e the distance of between two successive bright or dark fringe) is mathematically represented as

             \beta  = \frac{\lambda D}{d}

Where d is  the distance between the  slits

            \beta is the fringe width which can also be evaluated as

                         \beta = \frac{L}{n}

Substituting values

                        \beta = \frac{0.0398}{24}

                          \beta = 1.660 *10^{-3}

Making d the subject of formula in the above equation

                d = \frac{\lambda D}{\beta }

Substituting values

                d = \frac{406.192 *10^{-9} * 5.937 }{1.660 *10^{-3}}

                    d = 0.00145m                

           

4 0
4 years ago
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