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____ [38]
3 years ago
8

A new outdoor rec center is being built in hardford. The perimeter of the rectangular playing field is 258 yards. the length of

the field is 9 yards less than double the width. Whatre the dimensions of the playing field?
Mathematics
1 answer:
Taya2010 [7]3 years ago
5 0
P = 2(L + W)
P = 258
L = 2W - 9

258 = 2(2W - 9 + W)
258 = 2(3W - 9)
258 = 6W - 18
258 + 18 = 6W
276 = 6W
276/6 = W
46 = W <=== here is the width

L = 2W - 9
L = 2(46) - 9
L = 92 - 9
L = 83 <== here is the length
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