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3 years ago

Three useful applications of alkaline earth metals

1 answer:

7 0

Alkaline earth metals refer to a group of elements in the periodic table. They include beryllium, magnesium, calcium, strontium, barium, and radium. Main uses of these elements are given below. Beryllium: It is used in small amounts to make copper beryllium alloy that are very strong and hard.

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How many molecules are in 85g of silver nitrate?

maksim [4K]

<h3>Answer:</h3>

3.0 × 10²³ molecules AgNO₃

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table
Writing Compounds
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

85 g AgNO₃ (silver nitrate)

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

Step 3: Convert

Set up: $\displaystyle 85 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3})(\frac{6.022 \cdot 10^{23} \ molecules \ AgNO_3}{1 \ mol \ AgNO_3})$
Multiply/Divide: $\displaystyle 3.01313 \cdot 10^{23} \ molecules \ AgNO_3$

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

3.01313 × 10²³ molecules AgNO₃ ≈ 3.0 × 10²³ molecules AgNO₃

6 0

3 years ago

Plz answer question! Due Today!!! Question is in picture! Will make BRAINLIEST for first correct answer!!! No links plz!

iris [78.8K]

Answer:

I'd Go. B. weigh everything, let the reaction happen, then weigh everything again.

3 0

3 years ago

Read 2 more answers

Calculate %ic of the interatomic bonds for the intermetallic compound al6mn. on the basis of this result, what type of interatom

pashok25 [27]

Answer : % ionic character is 0.20%

Bonding between the two metals will be purely metallic.

Explanation: For the calculation of % ionic character, we use the formula

$\% \text{ ionic character}= [1-e^{\frac{-(X_A-X_B)^2)}{4}}]\times(100\%)$

where $X_A$ & $X_B$ are the Pauling's electronegativities.

The table attached has the values of electronegativities, by taking the values of Al and Mn from there,

$X_{Al}=1.61$

$X_{Mn}=1.55$

Putting the values in the electronegativity formula, we get

$\% \text{ ionic character}= [1-e^{\frac{-(1.61-1.55)^2)}{4}}]\times(100\%)$

= 0.20%

Now, there are 3 types of inter atomic bonding

1) Ionic Bonding: It refers to the chemical bond in which there is complete transfer of valence electrons between atoms

2) Covalent Bonding: It refers to the chemical bond involving the sharing of electron pairs between 2 atoms.

3) Metallic Bonding: It refers to the chemical bond in which there is an electrostatic force between the positively charged metal ions and delocalised electrons.

In $Al_6Mn$ compound, the % ionic character is minimal that is $\sim$ 0.20% and there are two metal ions present, therefore this compound will have metallic bonding.

8 0

3 years ago

A 2.75 kg sample of a substance occupies a volume of 250.0 cm3. Find its density in g/cm3.

satela [25.4K]

Density is 0.011 g/cm3.

5 0

3 years ago

Read 2 more answers

A sample of hydrogen gas is found to be 8.50 L at a temperature of 38.0 C and a pressure of 725mm Hg. Find the volume at STP.

Vsevolod [243]

Temp must be Kelvin
38 C = 311.15 K
Volume at STP = 8.50 liters * (273.15 / 311.15) * (725 / 760) =
 7.1182746306 Liters

The formula to use is:

Volume at STP = Present Volume * (273.15 / Present Temp °K) * (Present Pressure (Torr) / 760)

6 0

3 years ago