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Paul [167]
3 years ago
5

Three useful applications of alkaline earth metals

Chemistry
1 answer:
svetlana [45]3 years ago
7 0
Alkaline earth metals refer to a group of elements in the periodic table. They include beryllium, magnesium, calcium, strontium, barium, and radium. Main uses of these elements are given below. Beryllium: It is used in small amounts to make copper beryllium alloy that are very strong and hard.
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How many molecules are in 85g of silver nitrate?
maksim [4K]
<h3>Answer:</h3>

3.0 × 10²³ molecules AgNO₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Writing Compounds
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

85 g AgNO₃ (silver nitrate)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 85 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3})(\frac{6.022 \cdot 10^{23} \ molecules \ AgNO_3}{1 \ mol \ AgNO_3})
  2. Multiply/Divide:                                                                                                \displaystyle 3.01313 \cdot 10^{23} \ molecules \ AgNO_3

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

3.01313 × 10²³ molecules AgNO₃ ≈ 3.0 × 10²³ molecules AgNO₃

6 0
3 years ago
Plz answer question! Due Today!!! Question is in picture! Will make BRAINLIEST for first correct answer!!! No links plz!
iris [78.8K]

Answer:

I'd Go. B. weigh everything, let the reaction happen, then weigh everything again.

3 0
3 years ago
Read 2 more answers
Calculate %ic of the interatomic bonds for the intermetallic compound al6mn. on the basis of this result, what type of interatom
pashok25 [27]

Answer : % ionic character is 0.20%

              Bonding between the two metals will be purely metallic.

Explanation: For the calculation of % ionic character, we use the formula

\% \text{ ionic character}= [1-e^{\frac{-(X_A-X_B)^2)}{4}}]\times(100\%)

where X_A & X_B are the Pauling's electronegativities.

The table attached has the values of electronegativities, by taking the values of Al and Mn from there,

X_{Al}=1.61

X_{Mn}=1.55

Putting the values in the electronegativity formula, we get

\% \text{ ionic character}= [1-e^{\frac{-(1.61-1.55)^2)}{4}}]\times(100\%)

                                               = 0.20%

Now, there are 3 types of inter atomic bonding

1) Ionic Bonding: It refers to the chemical bond in which there is complete transfer of valence electrons between atoms

2) Covalent Bonding: It refers to the chemical bond involving the sharing of electron pairs between 2 atoms.

3) Metallic Bonding: It refers to the chemical bond in which there is an electrostatic force between the positively charged metal ions and delocalised electrons.

In Al_6Mn compound, the % ionic character is minimal that is \sim0.20% and there are two metal ions present, therefore this compound will have metallic bonding.

8 0
3 years ago
A 2.75 kg sample of a substance occupies a volume of 250.0 cm3. Find its density in g/cm3.
satela [25.4K]
Density is 0.011 g/cm3.
5 0
3 years ago
Read 2 more answers
A sample of hydrogen gas is found to be 8.50 L at a temperature of 38.0 C and a pressure of 725mm Hg. Find the volume at STP.
Vsevolod [243]
Temp must be Kelvin
38 C = <span> <span> <span> 311.15 </span> </span> </span> K
Volume at STP = 8.50 liters * (273.15 / 311.15) * (725 / 760) =
<span> <span> <span> 7.1182746306 </span> </span> </span> Liters

The formula to use is:

Volume at STP = Present Volume * (273.15 / Present Temp °K) * (Present Pressure (Torr) / 760)

6 0
3 years ago
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