Answer:
a) 43%
b) 0.122
c) 7.70 molal
d) 5.83 M
Explanation:
Step 1: Data given
Mass of H2SO4 = 571.6 grams
Density of H2SO4 = 1.329 g/cm³ this means 1.329 grams per 1 mL or 1329 grams per 1L
<em>a) Calculate mass percentage</em>
Mass % = (571.6 grams / 1329 grams)* 100% = <u>43%</u>
<em>b) Calculate mole fraction</em>
Number of moles H2SO4 = Mass H2SO4 / Molar mass H2SO4
Moles H2SO4 = 571.6 grams / 98.08 g/mol
Moles H2SO4 = 5.83 moles
Moles H2O = (1329 -571.6)/18.02 = 42.03 moles
Total moles = 5.83 + 42.03 = 47.86 moles
Mole fraction H2SO4 = Moles of solute (H2SO4)/ Total moles
Mole fraction H2SO4 = 5.83 moles / 47.86 moles
Mol fraction h2SO4 = <u>0.122</u>
<em>c) Calculate the molality</em>
Mass of solvent = 1329 grams - 571.6 grams = 757.4 grams = 0.7574 kg
Molality of H2SO4 = number of moles H2SO4 / mass of solvent
Molality H2SO4 = 5.83 moles / 0.7574 kg
Molality H2SO4 = <u>7.70 molal</u>
<em>d) Calculate Molarity </em>
Molarity H2SO4 = Number of moles H2SO4 / volume
Molarity H2SO4 = 5.83 moles / 1L = <u>5.83 M</u>
