16.94/18=.9411111
sig figs: 0.9411 mole of water
Agriculture, space exploration, and also for medical purposes.
Hope I helped :)
The theoretical proportion is given by the balanced chemical equation:
2 mol NBr / 3 mol Na OH
Then x mol NaOH / 40 mol NBr3 = 3mol NaOH/2 mol NBr3
Solve for x, x = 40 * 3/2 = 60 mol NaOH.
Given that there are 48 mol NaOH (less than 60) this is the limitant reactant and the other is the excess reactant.
Answer: NBr3..
i just learnt this recently but i need to look through my notes again.
C(5) + O2(g)
Hope this helped
