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vitfil [10]
4 years ago
5

An experimental set up involves a cell with pumps that maintain high K+ and Cl- concentrations outside of the cell, and high Na+

and PO2- inside of the cell. If the cell is permeable only to Cl-, what will be true after equilibration occurs?
Chemistry
1 answer:
nata0808 [166]4 years ago
8 0

Explanation:

On one side , there is high concentration of potassium ion and chloride ions. And on other sides high concentration of sodium ions and phosphate ions.

[K^+][Cl^-]|[Na^+][PO_2^{-}]

Cell is permeable only to chloride ions.As we can see that chloride ions are only present on the outside of cell .

As we know solute particles move from higher concentration to lower concentration side that is to equalize the concentration of solute particles on both sides. So, chloride ion will move inside the cell until the concentration of chloride ions become equal on both the sides which will result in swelling up of cell.

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kogti [31]

Answer:

C) 0.121 M

Explanation:

HCl + H₂O = H₃O⁺ + OH⁻

.121M              .121M

HCl is a strong acid . It will dissociate almost 100 % so the concentration of acid and hydronium ion formed will be equal . It is to be noted that hydronium ion is formed due to association of H⁺ and H₂O . H⁺ is formed due to ionisation of HCl .

So concentrtion of hydronium ion ( H₃O⁺ ) will be .121 M.

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6 0
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Answer:

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