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vitfil [10]
4 years ago
5

An experimental set up involves a cell with pumps that maintain high K+ and Cl- concentrations outside of the cell, and high Na+

and PO2- inside of the cell. If the cell is permeable only to Cl-, what will be true after equilibration occurs?
Chemistry
1 answer:
nata0808 [166]4 years ago
8 0

Explanation:

On one side , there is high concentration of potassium ion and chloride ions. And on other sides high concentration of sodium ions and phosphate ions.

[K^+][Cl^-]|[Na^+][PO_2^{-}]

Cell is permeable only to chloride ions.As we can see that chloride ions are only present on the outside of cell .

As we know solute particles move from higher concentration to lower concentration side that is to equalize the concentration of solute particles on both sides. So, chloride ion will move inside the cell until the concentration of chloride ions become equal on both the sides which will result in swelling up of cell.

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vlada-n [284]
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6 0
4 years ago
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Watch the animation and identify the correct conditions for forming a hydrogen bond. check all that apply. check all that apply.
OLga [1]
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A hydrogen bond is equivalent to a covalent bond.
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6 0
4 years ago
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Which statement below correctly describes the relationship between Q and K for both reactions? Are these reactions spontaneous a
nikklg [1K]

Answer:

Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.

Explanation:

Hello,

In this case, the undergoing chemical reactions with their proper Gibbs free energy of reaction are:

A->B;\Delta _rG^o=-13 kJ/mol

C ->D ;\Delta _rG^o=3.5 kJ/mol

The cellular concentrations are as follows: [A] = 0.050 mM, [B] = 4.0 mM, [C] = 0.060 mM and [D] = 0.010 mM.

For each case, the reaction quotient is:

Q_1=\frac{4.0mM}{0.050mM}=80\\ Q_2=\frac{0.010mM}{0.060mM}=0.167

A typical temperature at a cell is about 30°C, in such a way, the equilibrium constants are:

K_1=exp(-\frac{-13000J/mol}{8.314J/mol*K*303.15K} )=173.8\\K_2=exp(-\frac{3500J/mol}{8.314J/mol*K*303.15K} )=0.249

Therefore, Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.

Best regards.

6 0
3 years ago
C,H,O,+ 3HCI → C,HCl, + 3H20<br> right 5 possible mole ratios
Marina86 [1]

Answer:

Here's what I get  

Explanation:

I think this may be the equation you intended to write:

C₃H₅(OH)₃ + 3HCl ⟶ C₃H₅Cl₃ + 3H₂O

The mole ratios are the ratios of the coefficients in the balanced equation.

Here are some of the possible molar ratios.  

  1. C₃H₅(OH)₃:HCl        = 1:3
  2. C₃H₅(OH)₃:C₃H₅Cl₃ = 1:1
  3. C₃H₅(OH)₃:H₂O       = 1:3
  4.           HCl:C₃H₅Cl₃ = 3:1
  5.           HCl:H₂O       = 3:3
  6.    C₃H₅Cl₃:H₂O       = 1:3

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Answer:

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I just did the first 3 since I could easily access the proteins section in my textbook at the moment. :)

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