The amount of energy in kilocalories released from 49 g of glucose given the data is -4.4 Kcal
How to determine the mole of glucose
Mass of glucose = 49 g
Molar mass of glucose = 180.2 g/mol
Mole of glucose = ?
Mole = mass / molar mass
Mole of glucose = 49 / 180.2
Mole of glucose = 0.272 mole
How to determine the energy released
C₆H₁₂O₆ →2C₂H₆O + 2CO₂ ΔH = -16 kcal/mol
From the balanced equation above,
1 mole of glucose released -16 kcal of energy
Therefore,
0.272 mole of glucose will release = 0.272 × -16 = -4.4 Kcal
Thus, -4.4 Kcal were released from the reaction
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Answer: I think it's D
Explanation: None of the other options are true.
The ions are as follows;
- As2O3 - As^3+, O^2-
- MnS - Mn^2+, S^2-
- VCl3 - V^3+, Cl^-
- NiF2 - Ni^2+, F^-
<h3>What is a cation and an anion?</h3>
A cation is a positive ion while an anion is a negative ion. Ionic compounds are composed o cations and anions.
The anions and cations in the ionic compounds in the table are shown below;
- As2O3 - As^3+, O^2-
- MnS - Mn^2+, S^2-
- VCl3 - V^3+, Cl^-
- NiF2 - Ni^2+, F^-
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Answer:
Please find the complete question and its solution in the attached file:
Explanation:
